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3 years ago

Decrease £16855.21 by 3.5% give your answer rounded to 2 DP

Mathematics

1 answer:

Firdavs [7]3 years ago

6 0

The answer is £16265.28

That should be correct

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1. Suppose you spin the spinner shown below, which is divided into equal

Mashcka [7]

C is the correct answer choice

7 0

3 years ago

Pls help if you only know the correct answer! Thanks! :)

FromTheMoon [43]

Yes yes yes yes yes yes yes that is the makers Ik the answer it’s easy do you need help if so tell me

3 0

3 years ago

Given LaTeX: f\left(x\right)=x^{^3}-3x+4f ( x ) = x 3 − 3 x + 4, determine the intervals where the function is increasing and wh

Vedmedyk [2.9K]

Answer:

Increasing: $x$ and $x>1$ .

Decreasing: $-1$

Step-by-step explanation:

We have been given a function $f(x)=x^3-3x+4$ . We are asked to determine the intervals, where the function is increasing and where it is decreasing.

First of all, we will find critical points of our given function by equating derivative of our given function to 0.

Let us find derivative of our given function.

$f'(x)=\frac{d}{dx}(x^3)-\frac{d}{dx}(3x)+\frac{d}{dx}(4)$

$f'(x)=3x^{3-1}-3+0$

$f'(x)=3x^{2}-3$

Let us equate derivative with 0 as find critical points as:

$0=3x^{2}-3$

$3x^{2}=3$

Divide both sides by 3:

$x^{2}=1$

Now we will take square-root of both sides as:

$\sqrt{x^{2}}=\pm\sqrt{1}$

$x=\pm 1$

$x=-1,1$

We know that these critical points will divide number line into three intervals. One from negative infinity to -1, 2nd -1 to 1 and 3rd 1 to positive infinity.

Now we will check one number from each interval. If derivative of the point is greater than 0, then function is increasing, if derivative of the point is less than 0, then function is decreasing.

We will check -2 from our 1st interval.

$f'(-2)=3(-2)^{2}-3=3(4)-3=12-3=9$

Since 9 is greater than 0, therefore, function is increasing on interval $(-\infty, -1) \text{ or } x$ .

Now we will check 0 for 2nd interval.

$f'(0)=3(0)^{2}-3=0-3=-3$

Since -3 is less than 0, therefore, function is decreasing on interval $(-1,1) \text{ or } -1$ .

We will check 2 from our 3rd interval.

$f'(2)=3(2)^{2}-3=3(4)-3=12-3=9$

Since 9 is greater than 0, therefore, function is increasing on interval $(1,\infty) \text{ or } x>1$ .

6 0

4 years ago

Determine the domain and range of the given function.

myrzilka [38]

 here is your answer refer to the attachment

3 0

2 years ago

Read 2 more answers

The length of a rectangle is 2 feet longer than the width. the perimeter is 28 feet. find the dimensions of the rectangle.

schepotkina [342]

Perimeter=2l+2w

28=2l+2w
l=w+2

Substitute for l
28=2(w+2)+2w
28= 2w+4+2w
28=4w+4
24=4w
6=w

Plug the w value in
l=6+2
l=8

Final answer: Length=8 ft, Width=6 ft

5 0

3 years ago