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3 years ago

Three consecutive integers whose sum is 138

Mathematics

2 answers:

Virty [35]3 years ago

7 0

45 + 46 + 47 = 138

Hope this helps!

Klio2033 [76]3 years ago

7 0

X → first integer

X + 1 → second integer

X + 3 → third integer

X + X + 1 + X + 2 = 138

3x + 3 = 138

-3 -3

3x = 135

÷3 ÷3

X = 45

X + 1 = 46

X + 2 = 47

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10 points! Please help if able!

TEA [102]

The 30/60/90 right triangle is the biggest cliche in trig. We recall the sides come in ratio $1:\sqrt{3}:2$

$1:\sqrt{3}:2 = x:y:4\sqrt{2}$

First x:

$\dfrac x 1 = \dfrac{4 \sqrt{2}}{2}$

$x = 2 \sqrt 2$

Next y:

$\dfrac{y}{\sqrt{3}} =\dfrac{x}{1}$

$y= 2 \sqrt{2} \sqrt{3} = 2 \sqrt{6}$

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Kipish [7]

Answer:

Option 4 is correct. The length of PR is 6.4 units.

Step-by-step explanation:

From the given figure it is noticed that the triangle PQR and triangle MQR.

Let the length of PR be x.

Pythagoras formula

$hypotenuse^2=base^2+perpendicular^2$

Use pythagoras formula for triangle PQM.

$PM^2=QM^2+PQ^2$

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$PM^2=100$

$PM=10$

The value of PM is 10. The length of PR is x, so the length of MR is (10-x).

Use pythagoras formula for triangle PQR.

$PQ^2=QR^2+PR^2$

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Use pythagoras formula for triangle MQR.

$MQ^2=QR^2+MR^2$

$(6)^2=QR^2+(10-x)^2$

$36=QR^2+x^2-20x+100$

$36-x^2+20x-100=QR^2$ .... (2)

From equation (1) and (2) we get

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Answer:

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a rational number can be expressed as fraction. well, that is what the number 8/9 is.

so, A is a correct option.

as such it is automatically also a member of the real numbers (which is a superset of rational numbers). so, E is a correct option.

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it is not a whole number (0, 1, 2, 3, 4, ...).

it is not an integer (... , -2, -1, 0, 1, 2, 3, ...).

and as it is a rational number, it is automatically not an irrational number.

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2000, you just need to put three zeros at the end of the number.

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-1,2

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