Three consecutive integers whose sum is 138
2 answers:
45 + 46 + 47 = 138
Hope this helps!
X → first integer
X + 1 → second integer
X + 3 → third integer
X + X + 1 + X + 2 = 138
3x + 3 = 138
-3 -3
3x = 135
÷3 ÷3
X = 45
X + 1 = 46
X + 2 = 47
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