21-3= 18 and 18 divided by 6 equals 3 so v=3
Answer:
58
Step-by-step explanation:
1. let x be the unknown number
2. make an expression
x + 26/12 = 7/1
3. cross multiply
x +26 × 1 = x + 26
12 × 7 = 84
x + 26 = 84
4. move variables on one side and numbers on other side of the equal sign
x + 26 = 84
- 26 -26
x = 58
Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.
So there are 3 clubs:
- Club A, with 10 students.
- Club B, with 4 students.
- Club C, with 5 students.
The possible combinations of 2 students from different clubs are
- Club A with club B
- Club A with club C
- Club B with club C.
The number of combinations for each of these is given by the product between the number of students in the club, so we get:
- Club A with club B: 10*4 = 40
- Club A with club C: 10*5 = 50
- Club B with club C. 4*5 = 20
For a total of 40 + 50 + 20 = 110 different combinations.
This means that there are 110 different ways in which 2 students from different clubs can be selected.
If you want to learn more about combination and selections, you can read:
brainly.com/question/251701
Answer:
$110
Step-by-step explanation:
The computation is shown below:
Provided that
Number of desk purchased Fund Left $
0 700
1 590
2 480
3 370
4 260
5 150
6 40
Now the Fund decreased while purchasing is
= 5 desks - 2 desks
= 3 desks
i.e
= $480 - $150
= $330
Now the amount of money left for decreased the desk fund is
= $110
