Question

See ss belowplease show all work ​

Answer 1

Answer:

x = 117km

Step-by-step explanation:

a1 = 18 km

q = 90% = 90/100 = 0.9


a2 = a1 • q = 18 • 0.9 = 81/5 = 16.2 km

a3 = a2 • q = 16.2 • 0.9 = 729/50 = 14.58 km

n = 10

x = a1 • q^n - 1/q - 1 = 18 • 0.9^10 - 1/0.9 - 1 = 117km

Answer 2

Answer:

Solution given:

since Rosie walked 18 km INA first day.

so

first term[a]=18km

again

she walked 90% of what she walked the day before which means

common ratio decreasing

common ratio[r]90%=0.9

sum of 10th day$S_{10}$=?

no of term (n)=10

now

we have

$Sum_{10}=\frac{a(r^{n}-1)}{r-1}$

substituting value:

=$\frac{18(0.9^{10}-1)}{0.9-1}$

=117.28km

in nearest 10 it is 117km

the total distance Rosie had travelled by the end of 10 days is 117km.