8×5=40
40h-3=0
+3
40h=3
÷40
h=3/40
Follow the order of operations. PEMDAS. Parenthesis, Exponents, Multiplication, Division, Addition, and Subtraction. Let's start with parenthesis. First we so everything inside the parenthesis. So the first thing we do, is exponents, 2 x 2 = 4. Now the top equation is 3 x 4 - 23. Next thing in the order of operations, is Multiplication. So now we do 3 x 4. Which equals 12. Now the top equation is 10 - 12 - 23. Now we do Subtraction in order. First 10 - 12 = negative 2 (-2) Then we do -2 - 23 which equals negative 25 (-25). Now let's work on the bottom equation. Once again follow the order of operations. We do the exponents in the parenthesis first. 10 x 10 = 100. Then do the rest in the parenthesis, 1 + 100 = 101. Now the exponents in the outside of the parenthesis. - 2 x - 2 = 4. And 5 x 5 = 25. Then we do Multiplication, 4 x 25, which equals 100. Then we do 101 - 100 = 1. Then we reduce the fraction. -25/1 = -25. Therefore the answer to your problem is -25. I apologize for taking so long to write this. Hope this helps though!
-Twixx
Procedure:
1) Integrate the function, from t =0 to t = 60 minutues to obtain the number of liters pumped out in the entire interval, and
2) Substract the result from the initial content of the tank (1000 liters).
Hands on:
Integral of (6 - 6e^-0.13t) dt ]from t =0 to t = 60 min =
= 6t + 6 e^-0.13t / 0.13 = 6t + 46.1538 e^-0.13t ] from t =0 to t = 60 min =
6*60 + 46.1538 e^(-0.13*60) - 0 - 46.1538 = 360 + 0.01891 - 46.1538 = 313.865 liters
2) 1000 liters - 313.865 liters = 613.135 liters
Answer: 613.135 liters
slope = (y2-y1)/(x2-x1)
= (70-52)/(8-1)
= 18/7
=2.6
point slope form
y-y1 = m(x-x1)
y-52 = 2.6(x-1)
distribute
y-52 = 2.6x-2.6
add 52 to each side
y = 2.6x+49.4
y = 2.6x +49
the initial temperature is 49.4 or about 49
and it increases about 2.6 degrees each week
