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weqwewe [10]
3 years ago
10

Select all of the angles that are congruent to \angle 5.

Mathematics
1 answer:
ozzi3 years ago
5 0

Answer:

<5 = <8 b/c of vertical angles

<5 = <4 because of alternate interior angles

<5 = <1 because of corresponding angles

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Please help I’m struggling on this question.
timofeeve [1]

Answer: \frac{2(y^2-4y+40)}{(y-8)(y+4)}

Step-by-step explanation:

To solve this problem, we want to make sure the denominators are the same on both fractions. Once they are equal, we can dd them together.

\frac{y+4}{y-8} +\frac{y-8}{y+4}                      [multiply first fraction by y+4 and second by y-8]

\frac{(y+4)(y+4)}{(y-8)(y+4)} +\frac{(y-8)(y-8)}{(y-8)(y+4)}   [distribute by FOIL]

\frac{y^2+8y+16}{(y-8)(y+4)} +\frac{y^2-16y+64}{(y-8)(y+4)}   [add numerator]

\frac{y^2+8y+16+y^2-16y+64}{(y-8)(y+4)}         [combine like terms]

\frac{2y^2-8y+80}{(y-8)(y+4)}                       [factor out 2 from numerator]

\frac{2(y^2-4y+40)}{(y-8)(y+4)}                  

Now we know that \frac{2(y^2-4y+40)}{(y-8)(y+4)} is the factored form after adding.

5 0
3 years ago
Can someone help me with 11 and past that
Ilia_Sergeevich [38]
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4 years ago
Please help been stuck on this for so long.
suter [353]

Answer:

156

Step-by-step explanation:

156

156

156

156

156

156

15

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4 years ago
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zalisa [80]

-0.2

'0

-0.2 = - .2 = - 2/10 = - 1/5

so

answer is -1/5

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3 years ago
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baherus [9]
Wow collage seems so hard
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