3 years ago

Please assist me with this problem

Mathematics

1 answer:

tatiyna3 years ago

3 0

Put yes
because i did this

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USA Today surveyed fifty-five working parents and asked them if they feel they spend too little time with their children due to

Bezzdna [24]

Answer:

d. (0.5457 , 0.8361)

Step-by-step explanation:

From the missing findings recorded in the Excel output; we have:

the sample size to be = 55

count of response = 38

So, the proportion of parents that have the feeling they do spend little time with their children are :

p = $\dfrac{38}{55}$

p= 0.69

Thus, p = sample mean $\overline x$ = 0.69

The standard error of the proportion p is expressed as:

$S.E = \sqrt{\dfrac{p (1-p)}{n}}$

$S.E = \sqrt{\dfrac{0.69 (1-0.69)}{55}}$

$S.E = \sqrt{\dfrac{0.69 (0.31)}{55}}$

$S.E = \sqrt{\dfrac{0.2139}{55}}$

$S.E = \sqrt{0.003889}$

S.E = 0.06236

At 98% confidence interval level, the level of significance = 1 - 0.98 = 0.02

$z_{0.02/2} =2.326$

Confidence interval = $p \pm z_{0.02/2} \times S.E$

Confidence interval = $0.69 \pm 2.326 \times 0.062$

Confidence interval = $0.69 \pm 0.144212$

Confidence interval = $(0.69 - 0.144212 \ , \ 0.69 +0.144212 )$

Confidence interval = $(0.545788 \ , \ 0.834212 )$

Thus, option d. (0.5457 , 0.8361) is the right answer

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