3 years ago

Please assist me with this problem

Mathematics

1 answer:

tatiyna3 years ago

3 0

Put yes
because i did this

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Marcus observed that 8 of the 20 games that he had bowled last week were over 180. What percent of his games were over 180?

shepuryov [24]

Answer:

40%

Step-by-step explanation:

Ok so my brain is sorta not working but it said "hey! 20 divided by 2 is 10!"

So I was like ight and divided 80 by 2 to to get 40%.

Hope this helps.

6 0

2 years ago

For a treasure hunt game, 300 balls are hidden. Of the balls that ate hidden, 40% of them are yellow and the rest are white. Sal

Mamont248 [21]

300*.4=120
300-120=180

there are 120 yellow balls and 180 white balls.

120*.2=24
180*.8=144

sallys team found 168 balls

4 0

2 years ago

Read 2 more answers

Find the length of B to the nearest tenth using the Pythagorean theorem.

fgiga [73]

The answer is 11.2

The Pythagorean Theorem says
a^2+b^2=c^2

From the picture, we know one side, and the hypotenuse.

10^2+b^2=15^2
100+b^2=225
b^2=225
Sqrtb^2=sqrt225
b=11.18

Rounded to the nearest tenth it is 11.2

4 0

3 years ago

In this problem we will be dealing with the probability density function (pdf) associated with a continuous random variable, X.

konstantin123 [22]

Answer:

$b)\ 0.568$

Step-by-step explanation:

Given

$f(x) = 6x(1- x);\ 0 \le x \le 1$

Required

$P(0.3 < x < 0.7)$

From the question, we have:

$P(a < x < b) = \int\limits^b_a {f(x)} \, dx$

So, we have:

$P(0.3 < x < 0.7) = \int\limits^{0.7}_{0.3} {6x(1 - x)} \, dx$

Open bracket

$P(0.3 < x < 0.7) = \int\limits^{0.7}_{0.3} {6x - 6x^2} \, dx$

Integrate

$P(0.3 < x < 0.7) = \frac{6x^2}{2} - \frac{6x^3}{3}}|\limits^{0.7}_{0.3}$

$P(0.3 < x < 0.7) = 3x^2 - 2x^3|\limits^{0.7}_{0.3}$

Substitute 0.7 and 0.3 for x

$P(0.3 < x < 0.7) = (3*0.7^2 - 2*0.7^3) - (3*0.3^2 - 2*0.3^3)$

Using a calculator, we have:

$P(0.3 < x < 0.7) = (0.784) - (0.216)$

Remove brackets

$P(0.3 < x < 0.7) = 0.784 - 0.216$

$P(0.3 < x < 0.7) = 0.568$

3 0

2 years ago

5√√5 (54)³ =

Alex

Answer:

I hope you can see my writing clearly

4 0

1 year ago