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3 years ago

Please assist me with this problem

Mathematics

1 answer:

tatiyna3 years ago

3 0

Put yes
because i did this

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Given that f(x) = x2 − 3x + 3 and g(x) = the quantity of x minus one, over four , solve for f(g(x)) when x = 5. (1 point)

Anna007 [38]

Rewrite g(x) as x-1

------

and then substitute this result for x in f(x) = x^2 - 3x + 3:

f(g(x)) = (x-1)^2 / 4^2 - 3(x-1)/4 + 3.

At this point we can substitute the value 5 for x:

f(g(5)) = (5-1)^2 / 4^2 - 3(5-1)/4 + 3

= 16/16 - 3(4/4) + 3 = 1 - 3 + 3 = 1

Therefore, f(g(5)) = 1.

6 0

2 years ago

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Eduardwww [97]

2 number are x and y
X=10,y=65

8 0

3 years ago

The diagram is a straightedge and compass construction. A is the center of one circle,

mel-nik [20]

Answer:

All the points are the same distance from the center of line AB, therefore it is just the same triangle but rotated. They are the same triangle .

Step-by-step explanation:

5 0

3 years ago

Pls help, its probs gonna get deleted

Paladinen [302]

Sorry it took so long :)

3 0

2 years ago

Two terms of a geometric sequence are given. Find the first five terms. Please help asap

Zepler [3.9K]

Answer:

4, 8, 16, 32, 64

Step-by-step explanation:

The nth term of a geometric sequence is

$a_{n}$ = a₁ $(r)^{n-1}$

Given

a₇ = 256 and a₁₀ = 2048 , then

a₁ $r^{6}$ = 256 → (1)

a₁ $r^{9}$ = 2048 → (2)

Divide (2) by (1)

$\frac{a_{1}r^{9} }{a_{1}r^{6} }$ = $\frac{2048}{256}$

r³ = 8 ( take the cube root of both sides )

r = $\sqrt[3]{8}$ = 2

Substitute r = 2 into (1)

a₁ × $2^{6}$ = 256

a₁ × 64 = 256 ( divide both sides by 64 )

a₁ = 4

Then

a₁ = 4

a₂ = 2a₁ = 2 × 4 = 8

a₃ = 2a₂ = 2 × 8 = 16

a₄ = 2a₃ = 2 × 16 = 32

a₅ = 2a₄ = 2 × 32 = 64

7 0

2 years ago