Let's solve this by substitution.
y is given by the 2nd eqn as y = (1/3)x + 7. Subst. (1/3)x + 7 into the first eqn as a replacement for y: x + 9( (1/3)x + 7) = 3.
clear out fractions by mult. all 3 terms by 3: 3x + 9x + 63 = 3
Combine like terms: 12x = -60. Then x = -5
Find y by subst. -5 for x in the 2nd equation: y = (1/3)(-5) + 7
= -5/3 + 35/3 = 30/3 = 10.
Thus, the solution (x,y) of this system is (-5,10).
Answer:
setup below, you'll have to do the final calculation
Step-by-step explanation:
first perform the operation in parenthesis
2+39= 41
then do the multiplication 3 x 41
in general do calculations in this order
1. Parenthesis
2. Multiplication
3. Division
4. Addition
5. Subtraction
working from left to right
Answer: -10
Step-by-step explanation:
Difference between -17 & -7 should be
-17 - (-7)
-10
The question is defective, or at least is trying to lead you down the primrose path.
The function is linear, so the rate of change is the same no matter what interval (section) of it you're looking at.
The "rate of change" is just the slope of the function in the section. That's
(change in f(x) ) / (change in 'x') between the ends of the section.
In Section A:Length of the section = (1 - 0) = 1f(1) = 5f(0) = 0change in the value of the function = (5 - 0) = 5Rate of change = (change in the value of the function) / (size of the section) = 5/1 = 5
In Section B:Length of the section = (3 - 2) = 1 f(3) = 15f(2) = 10change in the value of the function = (15 - 10) = 5Rate of change = (change in the value of the function) / (size of the section) = 5/1 = 5
Part A:The average rate of change of each section is 5.
Part B:The average rate of change of Section B is equal to the average rate of change of Section A.
Explanation:The average rates of change in every section are equalbecause the function is linear, its graph is a straight line,and the rate of change is just the slope of the graph.
