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Alexeev081 [22]
2 years ago
12

Which point is located at (-3,6) A) A B) B C) C D) D

Mathematics
1 answer:
Andrej [43]2 years ago
3 0

Answer is A

Step-by-step explanation:

Go over to the left 3 times then up 6

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Can i get help plzz .....
wel

Answer:

$0.30

Step-by-step explanation:

If you already spent $5 then you have $6 remaining so you will just divide 6 and 20 and you will get 0.3 so $0.30

3 0
3 years ago
The gravitational force exerted by the planet Earth on a unit mass at a distance r from the center of the planet is:
jolli1 [7]

Answer:

Yes, F is a continuous function of r

Step-by-step explanation:

We are given that

When r<R

F(r)=\frac{GMr}{R^3}

r\geq R

F(r)=\frac{GM}{r^2}

Where M=Mass of the earth

R=Radius of earth

G=Gravitational constant

We have to find the function is continuous of r or not.

LHL

\lim_{r\rightarrow R-}\frac{GMr}{R^3}=\frac{GMR}{R^3}=\frac{GM}{R^2}

RHL

\lim_{r\rightarrow R+}\frac{GM}{R^2}=\frac{GM}{R^2}

F(R)=\frac{GM}{R^2}

When a function is continuous at x=a

Then, LHL=RHL=f(a)

RHL==LHL=F(R)

Hence, the function is continuous of r.

8 0
3 years ago
Leah's family traveled 5/7 of the distance to her grandmother’s house on Saturday. They traveled 1/2 of the remaining distance o
Paul [167]

Answer: 3/14

Step-by-step explanation:

They traveled 5/7 of the distance on Saturday and 1/2 of the remaining distance, 3/7 , on Sunday so...

(1/2)(3/7)= 3/14

Hope this helps :)

7 0
2 years ago
Read 2 more answers
A friend of yours claims that he can control the roll of a die, increasing his probability of rolling a six. you decide to put h
lana66690 [7]
Answer: No, I do not believe that there is enough convincing evidence to proof that he can control the dice.

When you roll a die, there is a 1/6 probability that you will roll a 6. If you multiply 50 by (1/6) you would expect your friend to roll at least 8 sixes.

He only rolled 3 more sixes than was expected. I would have him roll 50 more times at least to see how he does.
3 0
3 years ago
Which relation represents a function? StartSet (0, 0), (2, 3), (2, 5), (6, 6) EndSet StartSet (3, 5), (8, 4), (10, 11), (10, 6)
postnew [5]

Answer:

<h2>Third set.</h2>

(-2, 2), (0, 2), (7, 2), (11, 2)

Step-by-step explanation:

A function is defined as a relation where each x-value (domain), has only one y-vale assigned (range). If one x-value has more than one image in the range, therefore, that's not a function. So, let's see which relation represents a function.

First: (0, 0), (2, 3), (2, 5), (6, 6).

As you can see, this set doesn't represent a function, because for x=2 there are two images assigned y=3 and y=5.

Second: (3, 5), (8, 4), (10, 11), (10, 6).

Similarly, this relation is not a function, because x=10 has to images, y=11 and y=6.

Third: (-2, 2), (0, 2), (7, 2), (11, 2)

As you can see, this is a function, because each pair has different value in the domain. Notice that there's the same image for each x-value, that still fulfil the definition of a function, because one element in the image can have multiple elements in the domain, what cannot happen is the opposite case.

Fourth: (13, 2), (13, 3), (13, 4), (13, 5).

This relation is not a function, because the same x-value has multiple images.

Therefore, the right answer is the third set.

8 0
3 years ago
Read 2 more answers
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