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Vika [28.1K]
3 years ago
11

The drama club is selling tickets to their play to raise money for the show's expenses.

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
4 0

Answer:

I believe it would be 37

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8 ninths plus 5 twenty sevenths
Zigmanuir [339]
.13 since you are doing addition behind the period is ones tenth hundredth since 8+5=13 1 will be in the ones the 3 will be in the tenths place.
6 0
3 years ago
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One sample has Aa Aa One sample has n 10 scores and a variance of s2 20, and a second sample has n 15 scores and a variance of s
siniylev [52]

Answer:

option (a) It will be closer to 30 than to 20

Step-by-step explanation:

Data provided in the question:

For sample 1:

n₁ = 10

variance, s₁² = 20

For sample 2:

n₂ = 15

variance, s₂² = 30

Now,

The pooled variance is calculated using the formula,

S^{2}_{p} = \frac{(n_{1}-1)\times s^{2}_{1} +(n_{2}-1)\times s^{2}_{2}}{n_{1}+n_{2}-2}

on substituting the given respective values, we get

S^{2}_{p} = \frac{(10-1)\times 20 +(15-1)\times 30}{10+15-2}

or

S^{2}_{p} = 26.0869

Hence,

the pooled variance will be closer to 30 than to 20

Therefore,

The correct answer is option (a) It will be closer to 30 than to 20

4 0
3 years ago
What is the sum 2/6+7/6
galben [10]
9/6 or the simplified version is 1 1/2
6 0
3 years ago
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Which expression is equivalent to 7a³ (8a² + a)²-4a³?<br> Simplify.
valentina_108 [34]

7a³ (8a² + a)²-4a³ \\  \\ 7 {a}^{3}(8 { {a}^{2} + a)(8 {a}^{2} + a )} - 4 {a}^{3}  \\  \\ 7 {a}^{3} ( {8a}^{2} (8 {a}^{2} + a ) + a(8 {a}^{2} + a ) - 4 {a}^{3}  \\  \\ 7 {a}^{3} (64 {a}^{4}  +  8{a}^{3}  + 8 {a}^{3}  +  {a}^{2} ) - 4 {a}^{3}  \\  \\ 7 {a}^{3}  (64 {a}^{4}  +  16 {a}^{3}  +  {a}^{2} ) - 4 {a}^{3}  \\  \\ 448 {a}^{7}  + 112 {a}^{6}  + 7 {a}^{5}  - 4 {a}^{3}  \\  \\  {a}^{3} (448 {a}^{4}  + 112 {a}^{3}  + 7 {a}^{2}  - 4).

8 0
2 years ago
The ratio of dogs to cats is 2 to 3. There are 15 pets total. How many dogs are there? How many cats are there?
ElenaW [278]
So there are 2 dogs to every 3 cats (put into words)

in order to reach 15 total multiply both 2 and 3 by 3

2x3 = 6
3x3 = 9

so there are 6 dogs and 9 cats
6 0
3 years ago
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