3 years ago

In the diagram BC = 9. find AB and AC.

1 answer:

8 0

Answer:

where's the diagram can you tell

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olga55 [171]

If x=3+bi, then

$|x|=\sqrt{3^2+b^2}.$

You know that $|x|^2=13,$ then

$\left(\sqrt{3^2+b^2}\right)^2=13,\\ \\ 9+b^2=13,\\ \\b^2=4,\\ \\b=\pm 2.$

Two possible complex numbers satisfy these conditions:

$x_1=3+2i, \ x_2=3-2i.$

As you can see the possible value of b is 2.

Answer: correct choice is A.

3 0

3 years ago

Bezzdna [24]

Sorry on my device i cant read it

3 0

3 years ago

Ivahew [28]

You need more input here what even is the question

6 0

3 years ago

Alik [6]

The answer is b.......

4 0

3 years ago

Alexandra [31]

3(x + 5) = -4x + 8
3x + 15 = -4x + 8
3x + 4x = 8 - 15
7x = - 7
x = -7/7
x = -1

this equation has exactly 1 solution

6 0

4 years ago

In the diagram BC = 9. find AB and AC. ​