3 years ago

Please help me with this question please!

Mathematics

1 answer:

ss7ja [257]3 years ago

8 0

5 and 2/3 cakes an hour i will give u a cake if u mark me as brainliest

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The half-life of uranium-238 is 4.5x10^9 years. The half-life of uranium-234 is 2.5x10^5 years. How many times greater is the ha

lara31 [8.8K]

Answer:

Half-life of uranium-238 $18 \times 10^{3} \text { times greater }$ that of uranium-234

Explanation:

Half time of uranium-238 = $4.5\times 10^9$ years

Half time of Uranium-234 = $2.5\times 10^5$ years

To find how much times greater the half life of uranium-238 is from uranium-234

= $\frac{\text { Half life of Uranium-238 }}{\text { Half time of Uranium - 234 }}$

= $\frac{4.5 \times 10^{9}}{2.5 \times 10^{5}}$

= $18 \times 10^{3} \text { times greater }$

Hence Uranium-238 is $18 \times 10^{3} \text { times greater }$ than Uranium-234

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Answer:

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Slice the system of equations below 4×+y=16 and 2×+y=-2

BartSMP [9]

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Explanation:

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Plug x = 9 into 2x + y = -2

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