Answer:
ind the absolute value vertex. In this case, the vertex for y=−|x|−2 is (0,−2).
(0,−2)
The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.
Interval Notation:
(−∞,∞)
Set-Builder Notation: {x|x ∈ R}
For each x value, there is one y value. Select few x values from the domain. It would be more useful to select the values so that they are around the x value of the absolute value vertex.
x y
−2 −4
−1 −3
0 −2
1 −3
2 −4
Step-by-step explanation:
Answer:
Tell me if i am wrong. :)
Step-by-step explanation:
To solve for y:
Q.1 2x + y = -1
y = -1 - 2x
Q. 2. 4x - 5y = 7
y = 7 - 4x over -5
So you always want to pull out the gcf first but since there isn't one, we can move on.
so we can make an acb chart which is multiplying the a value and the c value and find factors that of that product that will equal the b value.
a value is 2
c value is -15
b value is 7
-30 factors to equal 7 = 10, -3
10 - 3 = 7
so the factors 10 and -3 work.
so now you make 2 separate parenthesis with one of the factors and one x. and it should be set equal to 0.
(x+10)(x-3) = 0
now solve for x in each separate parenthesis.
x = -10
x = 3
those r the roots
hope this helps
The answer is false, it is only true for postulates, not conjectures.
