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daser333 [38]
3 years ago
6

A(n) _____ is any side of a polygon that shares a side with only one angle of a pair of angles.

Mathematics
2 answers:
Wittaler [7]3 years ago
5 0

Answer: This type of angles are  adjacent interior angles.

erastovalidia [21]3 years ago
4 0

Answer:

non-included

Step-by-step explanation:

A non included side of a polygon shares a side with only one angle of a pair of angles.

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What is 881,635 ÷ 20 and remainder plaese
Sonbull [250]

Answer:

44,081 R 15

Step-by-step explanation:


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4 years ago
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1/2 times -1/4 PLEASEEEEEE
zysi [14]

Answer:-0.125 or 1/8

Step-by-step explanation: :)

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3 years ago
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Point J is on line segment IK. Given JK = 2x – 1, IK = 3x + 2,
Serhud [2]

Answer:

JK=7

Step-by-step explanation:

From the line segment, since J is on it ,it means the line segment is

represented as I J K

from this illustration, we can say that the longest part of the line segment is from I to K

this means that, IJ +JK =IK

making JK the subject,

JK= IK - IJ

but from the question, JK=2x-1 , IK=3x+2 and IJ=3x-5

substituting them in the expression,

2x-1 =3x+2 -(3x-5)

solving for x

2x-1 =3x+2-3x+5

2x-1 =0+7

2x-1 =7

2x=1+7

2x=8

dividing through by 2

2x/2 =8/2

x=4

but the question says we should find the numerical value for JK

but from the line segment,

JK=2x-1

but now we know the value of x to be 2

so substituting it in the formula

JK= 2(4)-1

JK=8-1

JK=7

therefore, the numerical value for JK is 7

4 0
3 years ago
I need the answer help<br>​
lisov135 [29]

Answer:

the second one(20)

Step-by-step explanation:

If you pretend 20 is x, you solve the equation by pluging in x (20) into the equation and it gives you 70, 70 is what the big part is and 70+20 is 90, which is the size of a 90degree side.

4(20)-10

80-10

70

70+20=90

3 0
3 years ago
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The hyperbolic orbit of a comet is represented on a coordinate plane with center at (0, 4). One branch has a vertex at (0, 10) a
Anuta_ua [19.1K]

Remember that

If the given coordinates of the vertices and foci have the form (0,10) and (0,14)

then

the transverse axis is the y-axis

so

the equation is of the form

(y-k)^2/a^2-(x-h)^2/b^2=1

In this problem

center (h,k) is equal to (0,4)

(0,a-k)) is equal to (0,10)

a=10-4=6

(0,c-k) is equal to (0,14)

c=14-4=10

Find out the value of b

b^2=c^2-a^2

b^2=10^2-6^2

b^2=64

therefore

the equation is equal to

<h2>(y-4)^2/36-x^2/64=1</h2><h2>the answer is option A</h2>
6 0
1 year ago
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