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stellarik [79]
3 years ago
11

Which equation, in point-slope form, passes through (-2, 4) and has a slope of 3?

Mathematics
1 answer:
spin [16.1K]3 years ago
8 0

Answer:

y=-2-3x

Step-by-step explanation:

Point-slope form: y-y1=m(x1-x)

In this problem, -2 is x1 and 4 is y1.

As always, m is the slope: 3.

Hence, plug these values into the equation.

y-4=3(-2-x)

Distribute the 3: 3(-2-x)= -6-3x

Now we have y-4=-6-3x

Because we want the y by itself, add 4 to each side of the equation.

y-4=-6-3x

  +4 +4

    y=-2-3x

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Given:

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                                    (g(x), f(u)) = ( 7*√x , e^u )

- The derivative of y is such that:

                                    y = f(g(x))

                                    y' = f' (g(x) ) * g'(x)

                                    y' = f'(u) * g'(x)

                                    y' = e^u* 3.5 / √x

- Hence,

                                   y ' = 3.5 * e^(7*√x) / √x

                               

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