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3 years ago

Which equation, in point-slope form, passes through (-2, 4) and has a slope of 3?

Mathematics

1 answer:

spin [16.1K]3 years ago

8 0

Answer:

y=-2-3x

Step-by-step explanation:

Point-slope form: y-y1=m(x1-x)

In this problem, -2 is x1 and 4 is y1.

As always, m is the slope: 3.

Hence, plug these values into the equation.

y-4=3(-2-x)

Distribute the 3: 3(-2-x)= -6-3x

Now we have y-4=-6-3x

Because we want the y by itself, add 4 to each side of the equation.

y-4=-6-3x

+4 +4

y=-2-3x

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Find the endpoint P of a line segment whose midpoint Q lies at (5, -10) and whose other endpoint lies at (-8, -4). Write it as a

blondinia [14]

P is (18, -16)

to find the answer, u would solve it in reverse order of the midpoint formula by first doing the x-values:

5(2)= 10-(-8) = 18

and then the same to y-values:

-10(2)= (-20)-(-4) = -16

to get:

(18, -16)

8 0

3 years ago

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algol [13]

Answer:

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Step-by-step explanation:

6 0

3 years ago

Find the midpoint of points A(8,-7) and B(3,-1) graphically

sukhopar [10]

Answer: (5.5, -4)

Step-by-step explanation:

You can use the midpoint formula to find the midpoint of point A and point B.

$M(\frac{x_{1}+x_{2} }{2}, \frac{y_{1} + y_{2} }{2})$

x₁ = 8

x₂ = 3

y₁ = -7

y₂ = -1

$M(\frac{x_{1}+x_{2} }{2}, \frac{y_{1} + y_{2} }{2})$

$M(\frac{8+3 }{2}, \frac{-7 +-1}{2} )$

$M(\frac{8+3 }{2}, \frac{-7 -1}{2} )$

$M(\frac{11 }{2}, \frac{-8}{2} )$

$M(5.5, -4 )$

Midpoint = (5.5, -4)

Hope this helps!

3 0

2 years ago

Helppppp i dont know pslßss

Natali5045456 [20]

Answer:

width=3

Step-by-step explanation:

area=length X width

length=4 X width

=>area=4 X width X width

=>area=(2 X width)^2

=>36=(2 X width)^2

=>6=2 X width

=>width=3

5 0

3 years ago

Read 2 more answers

HELP QUICK! You must find all intervals<br> where f(x) is negative. <br> f(x)=2(x+3)(x-7)

beks73 [17]

Answer:

any # where -2<=x<7

Step-by-step explanation:

(x-7) would be negative and (x+3) positive, resulting in f(x) being negative.

4 0

2 years ago