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AleksandrR [38]
2 years ago
8

I need help...... ..​

Mathematics
1 answer:
skelet666 [1.2K]2 years ago
3 0

Problem 27)

Refer to the diagram that says "problem 27".

This is the graph of y = 5x where x is the time in years, and y is the amount of simple interest in the account.

This equation comes from the simple interest formula below

i = P*r*t

i = 100*0.05*x

i = 5x

y = 5x

Note: The graph is a straight line through (0,0) and (1,5)

=====================================================

Problem 28)

The abscissa is the x coordinate. For a point like (-3, -7), the abscissa is -3.

The ordinate is the y coordinate. For that point mentioned earlier, the ordinate is -7.

The graph of points is shown below in the figure labeled "problem 28".

When graphing any point, we always start at the origin (0,0) where the x and y axis meet up. Then for a point like (-3,-7) we move 3 units to the left on the x axis and 7 units down on the y axis to arrive at point A. The other points are plotted in a similar fashion. The labels A,B,C,D are optional. They were added to help keep track of the points.

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Consider the statement "There are no simple solutions to life's problems."
aliya0001 [1]

Answer:

See below

Step-by-step explanation:

Remember the notation and rules of quantifiers. ∀ is the universal quantifier and ∃ is the existential quantifier. To negate ∀x p(x) , write ∃x ¬p(x). To negate ∃x p(x) , write ∀x ¬p(x)

Part I:

A) None of life's problems have a simple solution.

B) All of life's problems have a simple solution.

C) Some of life's problems have a simple solution

D) All of life's problems have a simple solution (notice how the original statements in B and D mean exactly the same)

E) Some of life's problems do not have a simple solution.

Part II: Let x be a variable representing one of life's problems, y be a variable representing solutions, p(x):="x has a simple solution", and q(x,y):="y is a simple solution of x".

A) (∀x)(¬p(x)) or ¬(∃x)(p(x))  

B) (∀x)(∃y)(q(x,y))

C) (∃y)(∀x)(q(x,y)). Note that the order of quantifiers is important. B) and C) have different meanings. In C) there is an universal solution of all problems, in B) each problem has its solution.

D) (∀x)(p(x))

E) Same as C)

4 0
3 years ago
Algebra 2: PLEASE HELP ME!!
vfiekz [6]

Looks more like Trig than Algebra II

They want us to apply the sum angle formula to \sin(x + \frac{5 \pi}{6})

5π/6 is 150°; I find it easier to think in degrees.

When the tangent of x is 3/4 that's a right triangle with opposite 3, adjacent 4 so hypotenuse 5. So a sine of 3/5 and a cosine of 4/5, both positive because we're told x is in the first quadrant.

The sine sum angle formula is

\sin(a+b) = \sin a \cos b + \cos a \sin b

\sin(x+\frac{5\pi}{6}) = \sin x  \cos \frac{5\pi}{6} + \cos x \sin \frac{5\pi}{6}

We know sin 150° = sin 30° = 1/2 and cos 150° = - cos 30° = -√3/2

\sin(x+\frac{5\pi}{6}) = \frac 3 5  (- \sqrt{3}/2)  + \frac 4 5 (1/2)

\sin(x+\frac{5\pi}{6}) = \dfrac{ 4- 3\sqrt{3}}{10}

Third choice

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