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3 years ago

If AB is parallel to CD, which statement must be true

Mathematics

2 answers:

Contact [7]3 years ago

8 0

AB and CD do not intersect.

HOPE it helps!!!!!!

sdas [7]3 years ago

5 0

If ab and cd are parallel they are the same

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45,133 lies between what and what

lana66690 [7]

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3 years ago

Mrs. lopez left for work at 6:35am. she arrived at work 40 minutes later. what time did she arrive at work?

Nadusha1986 [10]

Answer:

the answer will be 7:15 AM.

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4 0

3 years ago

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If there is 3/4 of pizza and it’s cut into 12/16 and everyone eats 2 slices how many slices are left

dedylja [7]

3/4=12/16 so 0 ? or is it something totally different

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3 years ago

You have two biased coins. Coin A comes up heads with probability 0.1. Coin B comes up heads with probability 0.6.However, you a

Andrews [41]

Answer:

The probability that our guess is correct = 0.857.

Step-by-step explanation:

The given question is based on A Conditional Probability with Biased Coins.

Given data:

P(Head | A) = 0.1

P(Head | B) = 0.6

<u>By using Bayes' theorem:</u>

$P(B|Head) = P(Head|B) \times \frac{P(B)}{P(Head)}$

We know that P(B) = 0.5 = P(A), because coins A and B are equally likely to be picked.

Now,

P(Head) = P(A) × P(head | A) + P(B) × P(Head | B)

By putting the value, we get

P(Head) = 0.5 × 0.1 + 0.5 × 0.6

P(Head) = 0.35

Now put this value in $P(B|Head) = P(Head|B) \times \frac{P(B)}{P(Head)}$ , we get

$P(B|Head) = P(Head|B) \times \frac{P(B)}{P(Head)}$

$P(B|Head) = 0.6 \times \frac{0.5}{0.35}$

$P(B|Head) = 0.857$

Similarly.

$P(A|Head) = 0.857$

Hence, the probability that our guess is correct = 0.857.

7 0

3 years ago

A container in the shape of a square-based prism has a volume of 2744 cm'. What dimensions give the

Vinvika [58]

Answer:

The dimensions that give the minimum surface area are:

Length = 14cm

width = 14cm

height = 14cm

And the minimum surface is:

S = 1,176 cm^2

Step-by-step explanation:

A regular rectangular prism has the measures: length L, width W and height H.

The volume of this prism is:

V = L*W*H

The surface of this prism is:

S = 2*(L*W + H*L + H*W)

If the base of the prism is a square, then we have L = W

Then the equations become:

V = L*L*H = L^2*H

S = 2*(L^2 + 2*H*L)

We know that the volume of the figure is 2744 cm^3

Then:

V = 2744 cm^3 = H*(L^2)

In this equation, we can isolate H.

H = (2744 cm^3)/(L^2)

Now we can replace this on the surface equation:

S = 2*(L^2 + 2*L* (2744 cm^3)/(L^2))

S = 2*L^2 + 4(2744 cm^3)/L

Now we want to minimize the surface area, then we need to find the zeros of the first derivative of S.

S' = 2*(2*L) - 4*(2744 cm^3)/L^2

This is equal to zero when:

0 = 2*(2*L) - 4*(2744 cm^3)/L^2

0 = 4*L*L^2 - 4*(2744 cm^3)

4*(2744 cm^3) = 4*L^3

2744 cm^3 = L^3

∛(2744 cm^3) = L = 14cm

Then the length of the base that minimizes the surface is L = 14.

Then we have:

H = (2744 cm^3)/(L^2) = (2744 cm^3)/(14cm)^2 = 14cm

Then the surface is:

S = 2*(L^2 + 2*L*H) = 2*( (14cm)^2 + 2*(14cm)*(14cm)) = 1,176 cm^2

8 0

3 years ago