Answer:
A) 7x^2-7x+15
Step-by-step explanation:
f(x) = 4x2 - 5x + 7,
g(x) = 3x2 - 2x + 8
f(x) +g(x) =
4x^2 - 5x + 7 + 3x^2 - 2x + 8=
7x^2-7x+15
Answer:
The answer is X * -1
Step-by-step explanation:
Answer:
36
Step-by-step explanation:
N = 6
S = 0 n = 1
2(1) - 1 = 1
S = 0 + 1 = 1
n = n + 1
n = 1 + 1
n = 2
S = 1 n = 2
2(2) - 1 = 3
S = 1 + 3 = 4
n = n + 1
n = 2 + 1
n = 3
S = 4 n = 3
2(3) - 1 = 5
S = 4 + 5 = 9
n = n + 1
n = 3 + 1
n = 4
S = 9 n = 4
2(4) - 1 = 7
S = 9 + 7 = 16
n = n + 1
n = 4 + 1
n = 5
S = 16 n = 5
2(5) - 1 = 9
S = 16 + 9 = 25
n = n + 1
n = 5 + 1
n = 6
S = 25 n = 6
2(6) - 1 = 11
S = 25 + 11 = 36
n = n + 1
n = 6 + 1
n = 7 > N
Stop
Answer: The second derivative would be
![f''(x)=5e^{-x}-50e^{-5x}](https://tex.z-dn.net/?f=f%27%27%28x%29%3D5e%5E%7B-x%7D-50e%5E%7B-5x%7D)
Step-by-step explanation:
Since we have given that
![f(x)=5e^{-x}-2e^{-5x}](https://tex.z-dn.net/?f=f%28x%29%3D5e%5E%7B-x%7D-2e%5E%7B-5x%7D)
We will find the first derivative w.r.t. 'x'.
So, it becomes,
![f'(x)=-5e^{-x}+10e^{-5x}](https://tex.z-dn.net/?f=f%27%28x%29%3D-5e%5E%7B-x%7D%2B10e%5E%7B-5x%7D)
Then, we will find the second derivative w.r.t 'x'.![f''(x)=5e^{-x}+10\times -5e^{-5x}\\\\f''(x)=5e^{-x}-50e^{-5x}](https://tex.z-dn.net/?f=f%27%27%28x%29%3D5e%5E%7B-x%7D%2B10%5Ctimes%20-5e%5E%7B-5x%7D%5C%5C%5C%5Cf%27%27%28x%29%3D5e%5E%7B-x%7D-50e%5E%7B-5x%7D)
Hence, the second derivative would be
![f''(x)=5e^{-x}-50e^{-5x}](https://tex.z-dn.net/?f=f%27%27%28x%29%3D5e%5E%7B-x%7D-50e%5E%7B-5x%7D)
Answer:
I am unable to underst6your question