Answer:
The lines will not intersect.
Step-by-step explanation:
I took the test and this was the correct answer, there isnt a solution.
6 orange. 42 total. 6/42 = 1/7 of the M&Ms are orange.
Answer:
8q + 6 = 8*2 + 6 = 16 + 6 = 22
Applying the formula for the area of a sector and length of an arc, the value of k is calculated as: 27.
<h3>What is the Area of a Sector?</h3>
Area of a sector of a circle = ∅/360 × πr²
<h3>What is the Length of an Arc?</h3>
Length of arc = ∅/360 × 2πr
Given the following:
- Radius (r) = 9 cm
- Length of arc = 6π cm
- Area of sector = kπ cm²
Find ∅ of the sector using the formula for length of acr:
∅/360 × 2πr = 6π
Plug in the value of r
∅/360 × 2π(9) = 6π
∅/360 × 18π = 6π
Divide both sides by 18π
∅/360 = 6π/18π
∅/360 = 1/3
Multiply both sides by 360
∅ = 1/3 × 360
∅ = 120°
Find the area of the sector:
Area = ∅/360 × πr² = 120/360 × π(9²)
Area = 1/3 × π81
Area = 27π
Therefore, the value of k is 27.
Learn more about area of sector on:
brainly.com/question/22972014
Answer:
Step-by-step explanation:
The hyperbola has x-intercepts, so it has a horizontal transverse axis.
The standard form of the equation of a hyperbola with a horizontal transverse axis is 
The center is at (h,k).
The distance between the vertices is 2a.
The equations of the asymptotes are
1. Calculate h and k. The hyperbola is symmetric about the origin, so
h = 0 and k = 0
2. For 'a': 2a = x₂ - x₁ = 3 - (-3) = 3 + 3 = 6
a = 6/2 = 3
3. For 'b': The equation for the asymptote with the positive slope is
Thus, asymptote has the slope of
4. The equation of the hyperbola is
The attachment below represents your hyperbola with x-intercepts at ±3 and asymptotes with slope ±2.
