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Pani-rosa [81]
3 years ago
14

I'm sorry someone help me out please thank you

Mathematics
1 answer:
USPshnik [31]3 years ago
5 0

Answer:

10 edges

6 faces

6 vertices

10 bases

Step-by-step explanation:

i’m kinda unsure for the bases but the rest are correct :/

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Item 5
Sedbober [7]

Answer: 300.3858/ maybe 300.385

Step-by-step explanation: 4 2/7 as decimal= 4.29 x (-18) = -77.22 x -3.89=  300.3858 (3.89 = decimal form of -3 8/9)  300.3858 x 1 = 300.3858

3 0
3 years ago
Leon graph y=12- 0.05 x to represent the number of gallons of gas left in his car after driving x miles.
mario62 [17]

Answer:

B

Step-by-step explanation:

Range of the graph is the ALLOWED y-values. The y-axis is number of gallons left in tank. So, <u><em>it cannot be NEGATIVE number of gallons, so 0 is the lower limit of the range.</em></u>

<u><em /></u>

As we can see from the axis of the graph, we see where the line cuts the y-axis, that is the upper limit of number of gallons he starts off with. The y-intercept (y-axis cutting point) is 12.

So we can say that the range is  0 ≤ y ≤ 12

Correct answer is B

5 0
3 years ago
25(y+1)-x^2(y+1) i don't know the answer
natita [175]
It seems like you've begun to group and factored out the GCF.

Because the inner binomials (the ones in parentheses) are the same, the next step is to rewrite the equation like so:

(25-x^2)(y+1)

From here, we can further factor (25-x^2) since they are both perfect squares.

(5+x)(5-x)(y+1)

No further terms can be factored so that is the final answer. Hope this helps!
7 0
3 years ago
Evaluate when x=5; X + 3*<br> 02
BaLLatris [955]

Answer:

The answer is 11

Step-by-step explanation:

The answer is 11 becasue if you substitute X for 5 the expression becomes 5+3*2 and 3*2 is 6 and 5+6 equals 11. if the two represents square (3 to the power of 2) the answer is 14 becasue 3 to the power of 2 is 9 and five plus nine is 14.

3 0
3 years ago
Find an equation of the line that bisects the acute angles formed by the lines with equations 2x+y-5=0 and 3x-2y+6=0
Neko [114]
The solving for the first one should be like this 

2x+y-5/sqrt 2^2 1^2=2x+y-5/sqrt5
And the next part 3x-2y+6/sqrt 3^2 -2^2=3x-2y+6/sqrt13

After these manipulations just multiply them 
&#10;(2sqrt13-3sqrt5)x+(sqrt13+2sqrt5) y-5sqrt13-6sqrt5=0 &#10;
And finally you need to square and simplify for the completed answer
5 0
3 years ago
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