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victus00 [196]
2 years ago
7

A geometric sequence has second term 12 and fifth term 324. A) find common ratio b) calculate 10th term c) the kth term is the f

irst term that is greater than 2000. Find the value of K
Mathematics
1 answer:
Alborosie2 years ago
6 0

Answer:

a) find common ratio = 3

b) calculate 10th term = 78732

c) k = 7

Step-by-step explanation:

A geometric sequence has second term 12 and fifth term 324.

a) find common ratio

Common ratio = r

Hence

We solve for this below:

r = cube root(fifth term/second term)

r = cube root (324/12)

r = cube root (27)

r = 3

Therefore, the common ratio = 3

b) calculate 10th term

The formula for a geometric sequence is given as:

an = ar^n-1

Where

a = First term

r = Common ratio = 3

n = Nth term = 10

Step 1

We have to find the first term

Common ratio = Second term/First term

Common ratio = 3

Second term = 12

Hence:

3 = 12/x

Cross Multiply

3x = 12

x = 12/3

x = 4

Hence , First term = 4

Step 2

We find the 10th term

an = ar^n-1

a10 = 4 × 3^10 - 1

a10 = 4 × 3⁹

a10 = 4 × 19683

a10 = 78732

Therefore, the 10th term = 78732

c) the kth term is the first term that is greater than 2000. Find the value of K

For kth term,

ak = ar^k-1 >2000

a = 4, r = 3

Hence

4 × 3^k-1 > 2000

We divide both sides by 4

4 × 3^k-1/4 > 2000/4

3^k-1 > 500

We take the logarithm of both sides

log 3^k-1 > log 500

k-1 log 3 > log 500

Divide both sides by log 3

k-1 log 3/log 3 > log 500/log 3

k - 1 > 5.6567800693

k > 5.6567800693 + 1

k > 6.6567800693

k = 7

Therefore, k = 7

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