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lesya692 [45]
3 years ago
13

What is a product of 10 and the counting numbers 1 2 3 and so on? Answer for 25 points!

Mathematics
1 answer:
natima [27]3 years ago
7 0
The product of all integers from 1 to 100 is 100!. The formula actually counts the number of factors 5 in n!, but since there are at least as many factors 2, this is equivalent to the number of factors 10, each of which gives one more trailing zero.May 15, 2020
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we believe that 42% of freshmen do not visit their counselors regularly. For this year, you would like to obtain a new sample to
Maksim231197 [3]

Answer:

A sample of 1077 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

42% of freshmen do not visit their counselors regularly.

This means that \pi = 0.42

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.

How large of a sample size is required?

A sample size of n is required, and n is found when M = 0.035. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.035 = 2.327\sqrt{\frac{0.42*0.58}{n}}

0.035\sqrt{n} = 2.327\sqrt{0.42*0.58}

\sqrt{n} = \frac{2.327\sqrt{0.42*0.58}}{0.035}

(\sqrt{n})^2 = (\frac{2.327\sqrt{0.42*0.58}}{0.035})^2

n = 1076.8

Rounding up:

A sample of 1077 is required.

3 0
3 years ago
Item 20 A rectangular school banner has a length of 54 inches and a width of 36 inches. A sign is made that is similar to the sc
siniylev [52]

Answer:

The ratio of the area of the school banner to the area of the sign is <u>1944 cubic inches : 192.61 cubic inches.</u>

Step-by-step explanation:

Given:

A rectangular school banner has a length of 54 inches and a width of 36 inches. A sign is made that is similar to the school banner and has a length of 17 inches.

Now, to find the ratio of the area of the school banner to the area of the sign.

Dimensions of school banner :

Length = 54 inches.

Width = 36 inches.

Dimension of school sign:

Length = 17 inches.

So, to we find the width of sign by using cross multiplication method:

Let the width be x.

So, 54 is equivalent to 36.

Thus, 17 is equivalent to x.

\frac{54}{36} =\frac{17}{x}

By cross multiplying we get:

54x=612

Dividing both sides by 54 we get:

x=11.33\ inches.

Thus, the width of sign = 11.33 inches.

Now, to get the ratio of the area of the school banner to the area of the sign:

Area of the school banner : Area of the school sign.

= 54\times 36:17\times 11.33

= 1944:192.61

Therefore, the ratio of the area of the school banner to the area of the sign is 1944 cubic inches : 192.61 cubic inches.

6 0
3 years ago
Read 2 more answers
There are 200 9th graders in the freshman class. 2/5 of the students are girls. How
alekssr [168]

Answer: 80

Step-by-step explanation:

7 0
2 years ago
The price of a coffee machine is £86.00. The price is going to increase by 20% a) What is the multiplier for a 20% increase? b)
Vlad1618 [11]

Answer:

86 * 0.2 = 17.2

<u><em>17.2 + 86 = 103.2</em></u>

Step-by-step explanation:

A) the multiplier is <u><em>0.2 </em></u>

B) The price is <em><u>103.2</u></em>


6 0
3 years ago
50 POINTS AND BRAINLY PLEASE HELP!!!
fomenos

Answer:Jason’s salary depends on the number of hours he works. The independent variable is the number of hours and the dependent variable is salary. Let x = the number of hours worked Let y = Jason’s salary The set of ordered pairs {(1, 10), (2, 20), (3, 30), (4, 40), (5, 50)} can be used to represent the function, assuming Jason earns $10 per hour The number of hours the train takes depends on the distance. The distance is independent and the number of hours is dependent. {(2,20)(4,40)(6,60)(8,80)(10,100)} For every 2 hours it takes 20 miles. The amount of money depends on the time worked.


Step-by-step explanation:


7 0
3 years ago
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