Question

3^2 - 2x + 4 and g(x) = 5x^2 + 6x - 8 find f-g(x)

Answer 1

Answer:

For the given functions f(x) and g(x) $(f-g)(x) = -2x^{2} - 8x +12$

Step-by-step explanation:

Here, the given function are:

$f(x) = 3x^{2} - 2x+ 4\\g(x) = 5x^{2} + 6x -8$

Now, simplifying for (f-g)(x)  =  f(x) -  g(x):

$f(x) - g(x) = (3x^{2} - 2x+ 4) - (5x^{2} + 6x -8)$

 $= 3x^{2} - 2x+ 4- 5x^{2} - 6x +8$

Doing operation on LIKE TERMS,  we get

f(x) -  g(x) = $( 3x^{2}- 5x^{2}) + (-2x - 6x) +( 4 +8) = -2x^{2} - 8x + 12$

Hence, for the given functions f(x) and g(x) $(f-g)(x) = -2x^{2} - 8x +12$