Answer:
The equation 'log Subscript 3 Baseline (negative 2 x minus 3) = 2' i.e.
has x = –6 as the solution.
Step-by-step explanation:
<u>Checking the equation</u>
log Subscript 3 Baseline (negative 2 x minus 3) = 2
Writing in algebraic expression

Use the logarithmic definition








Therefore, the equation 'log Subscript 3 Baseline (negative 2 x minus 3) = 2' i.e.
has x = –6 as the solution.
It doesn't, it ends after 32 digits after 0.
Answer:
s = 33
Step-by-step explanation:
99=3s
(99/3) = s
s=33