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never [62]
3 years ago
9

Standar form of 1.204751131

Mathematics
1 answer:
densk [106]3 years ago
6 0

1.204751131 × 10^{0}

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What is m<br> A.55°<br> B.58°<br> C.122°<br> D.125°
Andreyy89

Answer: k = 55 degrees

Step-by-step explanation:

to find J, subtract 122 from 180, you get 58. The total number of degrees is 180. Since L is given as 67, and 67+58=125. Simply subtract 125 from 180 which is 55 degrees

5 0
3 years ago
60% is equal to what fraction in simplest form?
e-lub [12.9K]

Answer:

3/5

Step-by-step explanation:

60 percent is the fraction 60/100 and simplifyping that by ten is 6/10

6/10 divided by two is 3/5

5 0
3 years ago
(c). It is well known that the rate of flow can be found by measuring the volume of blood that flows past a point in a given tim
aleksklad [387]

(i) Given that

V(R) = \displaystyle \int_0^R 2\pi K(R^2r-r^3) \, dr

when R = 0.30 cm and v = (0.30 - 3.33r²) cm/s (which additionally tells us to take K = 1), then

V(0.30) = \displaystyle \int_0^{0.30} 2\pi \left(0.30-3.33r^2\right)r \, dr \approx \boxed{0.0425}

and this is a volume so it must be reported with units of cm³.

In Mathematica, you can first define the velocity function with

v[r_] := 0.30 - 3.33r^2

and additionally define the volume function with

V[R_] := Integrate[2 Pi v[r] r, {r, 0, R}]

Then get the desired volume by running V[0.30].

(ii) In full, the volume function is

\displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr

Compute the integral:

V(R) = \displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr

V(R) = \displaystyle 2\pi K \int_0^R (R^2r-r^3) \, dr

V(R) = \displaystyle 2\pi K \left(\frac12 R^2r^2 - \frac14 r^4\right)\bigg_0^R

V(R) = \displaystyle 2\pi K \left(\frac{R^4}2- \frac{R^4}4\right)

V(R) = \displaystyle \boxed{\frac{\pi KR^4}2}

In M, redefine the velocity function as

v[r_] := k*(R^2 - r^2)

(you can't use capital K because it's reserved for a built-in function)

Then run

Integrate[2 Pi v[r] r, {r, 0, R}]

This may take a little longer to compute than expected because M tries to generate a result to cover all cases (it doesn't automatically know that R is a real number, for instance). You can make it run faster by including the Assumptions option, as with

Integrate[2 Pi v[r] r, {r, 0, R}, Assumptions -> R > 0]

which ensures that R is positive, and moreover a real number.

5 0
3 years ago
Solution for the inequality 6x +9 ≤ 27
AlexFokin [52]

Answer:

6x + 9 = 27

       -9     -9

6x = 18           Now divide both sides by 6

/6      /6            so the answer is 3

Step-by-step explanation:

5 0
3 years ago
Multiply the equation 2x+2y=8 by 3. Does the equation have the same solution set?
stepan [7]

Multiply the equation:

2x+2y=8 \mapsto 6x+6y=24

The solution set is the same, because multiplying both sides of an equation by a non-zero number doesn't change the solution set. In fact, if you rewrite the equation as

2x+2y-8=0

Multiplying this by 3 (or whatever number, for all it matters) gives

3(2x+2y-8)=0

Now, a product is zero if and only if at least one of the factor is zero. So, either 3=0 or 2x+2y-8=0

Since the first is clearly impossible, the second one must be true, which is the original equation.

3 0
3 years ago
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