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scoray [572]
3 years ago
8

Write in slope intercept form of an equation of the line through (5,-2) with a slope of 3/5

Mathematics
1 answer:
aliina [53]3 years ago
5 0
Hope it helps :))
Here is the working

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the answer is 5. 7-2 is 5.

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Simplify the expression \[\frac{6}{\sqrt{36} + \sqrt{27}} + \frac{6}{\sqrt{27} + \sqrt{18}} + \frac{6}{\sqrt{18} + \sqrt{9}}.\]
Viktor [21]

Answer:

= 18 ( 3 + 2(\sqrt{3}  + \sqrt{2} ))

Step-by-step explanation:

6(\sqrt{36} +\sqrt{27}) + 6(\sqrt{27} +\sqrt{18}) + 6(\sqrt{18} + \sqrt{9} )\\= 6( {6} +\sqrt{9*3}) + 6( \sqrt{9*3}  +\sqrt{9*2}) + 6(\sqrt{9*2} + 3 )\\= 6( {6} +3\sqrt{3}) + 6(3\sqrt{3} +3\sqrt{2}) + 6(3\sqrt{2} + 3 )\\=36 + 18\sqrt{3} + 18\sqrt{3} + 18\sqrt{2}+ 18\sqrt{2} + 18\\= 36+18  +18( \sqrt{3}+ \sqrt{3} +\sqrt{2} + \sqrt{2})\\= 54 + 18 (2\sqrt{3} +2\sqrt{2})\\=54 + 36\sqrt{3}  + 36\sqrt{2}\\= 18 ( 3 + 2(\sqrt{3}  + \sqrt{2} ))

7 0
3 years ago
Select the best possible first step to solving the system by first eliminating the x variable.
zheka24 [161]
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3 0
3 years ago
Help please!!! Find the area of the shaded region. All angles are right angles
kompoz [17]

Answer:

Area = 147 m^{2}

Step-by-step explanation:

The area of the shaded region is equal to the total area of the full square minus the area of the non shaded region.

The area of a rectangle is its base times its high

So A=b*a.

For the full square, A1=9m*23m=207m^{2}

For the non shaded square, A2 = 15m * 4m = 60m^{2}

So the shaded area is A1-A2 = 207 m^{2} -60 m^{2} = 147 m^{2}

8 0
3 years ago
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