Write each function in standard form g(x) = 2(x + 6)2

Kyle went to the store and bought a binder for 3.95, and a backpack for 34.49, and a calculator for 29.99. How much money did he

Murljashka [212]

He spent 68.43 at the store

6 0

4 years ago

What is 1023x102+112-5=

kiruha [24]

Answer:

The answer is 104,453.

Step-by-step explanation:

Multiply 1,023 and 102 first because you always have to do your problems left to right in math. Your equation should now look like 104,346 + 112 - 5. Calculate the sum of the positive numbers by adding 104, 346 + 112. Your equation should now be 104,458 - 5. Then lastly, you subtract the numbers 104,458 and 5, and you should get 104, 453 as your answer.

7 0

4 years ago

Read 2 more answers

HELP PLEASEEE YOULL GET 15 POINTS

katrin2010 [14]

Answer:

2.5 KPH

Step-by-step explanation:

3 0

2 years ago

COEFFICIENTS AND VARIABLES! PLEASE SOLVE ALL ASAP! ANSWER = BRAINLIEST

sweet [91]

no hhahahahahahaahahaahahhaahha

6 0

3 years ago

A magazine conducts an annual survey in which readers rate their favorite cruise ship. All ships are rated on a 100-point scale,

Lyrx [107]

Answer:

a) The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =85.82-81.90=3.92$

b) $SE=\sqrt{(\frac{4.55^2}{35}+\frac{3.97^2}{44})}=0.975$

And the Margin of error is given by:

$Me= z_{\alpha/2} * SE=1.96*0.975=1.910$

c) The 95% confidence interval would be given by $2.009 \leq \mu_1 -\mu_2 \leq 5.83$ .

Step-by-step explanation:

Notation and previous concepts

$n_1 =35$ represent the sample of ships that carry fewer than 500 passengers

$n_2 =44$ represent the sample of ships that carry 500 or more passengers

$\bar x_1 =85.82$ represent the mean sample of of ships that carry fewer than 500 passengers

$\bar x_2 =81.90$ represent the mean sample of of ships that carry 500 or more passengers

$\sigma_1 =4.55$ represent the population deviation of ships that carry fewer than 500 passengers

$\sigma_2 =3.97$ represent the sample deviation of ships that carry 500 or more passengers

$\alpha=0.05$ represent the significance level

Confidence =95% or 0.95

The confidence interval for the difference of means is given by the following formula:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{(\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2})}$ (1)

Part a

The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =85.82-81.90=3.92$

Part b: At 95% confidence, what is the margin of error?

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$