Question

Use sigma notation to represent the sum of a geometric series with a first term of 3 and a common ratio of . A. B. C. D.

Answer 1

Answer:

$\Sigma_{k=1}^{n}[3(\frac{10}{9} )^{k-1}]$

Step-by-step explanation:

A geometric sequence is a list of numbers having a common ratio. Each term after the first is gotten by multiplying the previous one by the common ratio.

The first term is denoted by a and the common ratio is denoted by r.

A geometric sequence has the form:

a, ar, ar², ar³, . . .

The nth term of a geometric sequence is $ar^{n-1}$

Therefore the sum of the first n terms is:

$\Sigma_{k=1}^{n}(ar^{k-1})$

Given a geometric series with a first term of 3 and a common ratio of 10/9, the sum of the first n terms is:

$\Sigma_{k=1}^{n}[3(\frac{10}{9} )^{k-1}]$