All categories

3 years ago

What angles of rotational symmetry are there for a regular hexagon?

Mathematics

1 answer:

adell [148]3 years ago

8 0

Answer:

60°, 120°, 180°, 240° and 300°

Step-by-step explanation:

In case of a regular hexagon, there is a set of six movements to complete its one rotation. Now in one rotation, it will complete 360° of its circular motion. Now the formula to calculate the angle of rotation for any shape with equal length of its sides is:

Angle of rotation (Ф) = 360/Total number of sides

In this case, Ф = 360/6

Ф = 60

This formula is valid for every shape with equal sides, like in case of pentagon you will have 360/5 to calculate the angle of rotation.

Now in case of hexagon, at rotation of 60°, its rotation is symmetrical, which means rotation will not change its physical appearance, this is the case for next 60° rotation as well, or you can say that for 120° (60° before and 60° afterwards). This suit will follow for all the angles given in the answer section.

You might be interested in

Write the number in two other forms 8.517

8090 [49]

8,517 8,000+500+10+7

7 0

3 years ago

The US postal service delivered 7.14 x 1010 pieces of mail in the month of December and 3.21 x 1010 in the month of January. Wha

ICE Princess25 [194]

I assume that the numbers are supposed to be written as 7.14 x 10^10 for December and 3.21 x 10^10. The total mail delivered is the sum of these two numbers.
(7.14 x 10^10) + (3.21 x 10^10) = 1.035 x 10^11

3 0

3 years ago

Read 2 more answers

SOMEONE PLEASE HELP ME ASAP PLEASE!!!!

ehidna [41]

Answer:

Therefore,

$a_{21}=2$

Step-by-step explanation:

Given:

$A=\left[\begin{array}{ccc}3&6&9\\2&4&8\\\end{array}\right]$

To Find:

a₂₁ = ?

Solution:

Let,

$A=\left[\begin{array}{ccc}a_{11}&a_{12}&a_{13}\\a_{21}&a_{22}&a_{23}\\\end{array}\right]$

We require ' a₂₁ ' i.e Second Row First Column Element

So on Comparing we get

∴ $a_{21}=2$

Therefore,

$a_{21}=2$

5 0

2 years ago

In B E C, F is the centroid, and AC = 12. Find A F and F C

klemol [59]

bearing in mind that the centroid in a triangle cuts each of the three medians in a 2:1 ratio.

since we know that A C = 12, let's split it in a 2:1 ratio then, cleary from the picture the larger is F C, so F C : A F is on a 2:1 ratio.

$\bf A C=A F+F C\qquad \qquad \cfrac{F C}{A F}=\cfrac{2}{1}\qquad \qquad \cfrac{2\cdot \frac{12}{2+1}}{1\cdot \frac{12}{2+1}}\implies \cfrac{2\cdot 4}{1\cdot 4}\implies \cfrac{8}{4}$

4 0

3 years ago

BRAINLIEST ANSWERS!One water molecule

zzz [600]

Um I think 4 i hope this helps

8 0

2 years ago