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vovangra [49]
2 years ago
8

What is the smallest 3-digit palindrome that is divisible by both 3 and 4?

Mathematics
1 answer:
kirill [66]2 years ago
4 0

Answer:

252

Step-by-step explanation:

To be divisible by 3, it's digits have to add to a number that is a multiple of 3.

To be divisible by 4 its last 2 digits have to be divisible by 3.

So let's start with 1x1 which won't work because 1x1 is odd. so let's go to 2x2 and see what happens.

212 that's divisible by 4 but not 3

222 divisible by 3 but not 4

232 divisible by 4 but not 3

242 not divisible by either one.

252 I think this might be your answer

The digits add up to 9 which is a multiple of 3 and the last 2 digits are divisible by 4

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Solve for x.<br> 3(2x + 5) = 33
Umnica [9.8K]

Answer:

x = 3

Step-by-step explanation:

3(2x + 5) = 33

3 * 2x + 3 * 5 = 33

6x + 15 = 33

6x = 33 - 15

x = 18 / 6

x = 3

6 0
2 years ago
If the quotient of 3/8 and 2 is subtracted from the product of 1 3/4 and 8/12 what is the difference please help
aleksandr82 [10.1K]

Answer:

47 / 48

Step-by-step explanation:

Quotient of 3/8 and 2

3/8 ÷ 2

3/8 * 1/2

= 3 /16

1 3/4 * 8/12

7/4 * 8/12

= 56/48

56/48 - 3/16

L. C. M of 48 and 16 = 48

(56 - 9) / 48

= 47 / 48

5 0
2 years ago
GARY DREW A RECTANGLE WITH A PERIMETER OF 20 INCHES. WHAT COULD BE THE LENGTH,WIDTH,AND AREA FOR THE RECTANGLE THAT GARY DREW?
Ilia_Sergeevich [38]
Assume L=1.5W, where W=width, L= Length of the triangle.

Therefore,

Perimeter (P) = 2(W+L) = 2(W+1.5W) = 2(2.5W) = 5W=20 => W=20/5 = 4 in

Then, L=1.5W = 1.5*4 = 6 in

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8 0
3 years ago
Simplify (8x^3-5x-1)-(7x^2+6x-10)
irakobra [83]

Answer:

8x^3-7x^2-11x+9

Step-by-step explanation:

(8x^3-5x-1)-(7x^2+6x-10)

remove unnesasary ( )

8x^3-5x-1 -(7x^2+6x-10)

the distribute

8x^3-5x-1 -7x^2-6x+10

combine like terms

8x^3-11x+9-7x^2

use the communative property to reorder the equation

8x^3-7x^2-11x+9

4 0
2 years ago
Suppose that there are five young women and six young men on an island. Each woman is willing to marry some of the men on the is
pochemuha

Answer:

Based on the current information, the last man remaining unmarried will be a choice between two

Jason marries Anna

Matt marries Elizabeth

Kevin marries Barbara

Larry marries Diane

Carol can marry either Nick or Oscar

Step-by-step explanation:

The basic method to sort which woman will be marrying which man is simple.

We have to extract the choice by comparing choices of each woman side by side and then selecting the least common one and hence sorting one by one.

First, let's name all the women and men

1. Anna

2. Barbara

3. Carol

4. Diane

5. Elizabeth

We will refer to them with the initial letter of their name . A for Anna, B for Barbara, C for Carol, D for Diane, E for Elizabeth.

The men :

1. Jason

2. Larry

3. Matt

4. Kevin

5. Oscar

6. Nick

And they will be referred as J for Jason, L for Larry, M for Matt, K for Kevin, O for Oscar  and N for Nick.

Options for A : J , L ,M

Options for B : K, L

Options for C : J, N , O

Options for D : J, L , N , O

Options for E : J, M

As we can see , no one else wants Kevin other than Barbara so :

Kevin marries Barbara

Moving onwards:

Elizabeth can marry either Jason or Matt,

Meanwhile Anna can marry either Jason , Larry or Matt  

Hence,

Matt marries Eilzabeth

as Anna has two more choices still which are Jason and Larry.

Further, seeing the options for Carol and Diane

Carol can marry either Jason, Nick or Oscar while Diane can marry Larry as well as Jason , Nick and Oscar

We can select Jason as the match for Anna as Larry is also a choice for Diane.

Hence, Jason marries Anna

Now we are left with Larry , Nick and Oscar.

Since Carol can only decide from Nick and Oscar but Diane can decide from Larry, Nick and Oscar. Larry is the ideal option for Diane

so, Larry marries Diane

Now in the end, Carol can either choose between Nick or Oscar.

If she chooses Nick to marry, Oscar is left single

If she chooses Oscar to marry, Nick is left single.

7 0
2 years ago
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