All categories

2 years ago

V=s^2+ 1/2sh, solve for H.

1 answer:

vladimir1956 [14]2 years ago

3 0

V = s^2 +1/2sh
Reorder so common terms are on one side.
s^2 +(sh)/2 = v
Subtract s^2 from both sides.
(sh)/2 = -s^2 +v
Multiply both sides of the equation by 2.
sh = -s^2 *2 +v *2
Simplify each term.
sh = -2s^2 +2v
Divide each term by s and simplify.

h = -2s + (2v)/s

You might be interested in

-10(1 - 9x) + 6(x - 10) Pics pls

Galina-37 [17]

Answer:

$\boxed{\sf{96x-70}}}$

Step-by-step explanation:

Use the distributive property.

<h3>What is a distributive property?</h3>

Distributive property is a serving to distribute or allot or disperse.

Distributive property:

A(B+C)=AB+AC

A(B-C)=AB-AC

-10(1-9x)+6(x-10)

Expand.

-10(1-9x)

-10*1=-10

-10*9x=90x

$\longrightarrow \sf{=-10+90x+6\left(x-10\right)}}$

6(x-10)

6*x=6x

6*10=60

6x-60

Rewrite the problem down.

= -10+90x+6x-60

Combine like terms.

90x+6x-10-60

Add the numbers from left to right.

90x+6x=96x

96x-10-60

Finally, subtract the numbers from left to right.

-10-60=-70

$\Longrightarrow \boxed{\sf{96x-70}}$

Therefore, the final answer is 96x-70.

I hope this helps, let me know if you have any questions.

To learn more about distributive property:

brainly.com/question/2807928

#SPJ1

3 0

1 year ago

Read 2 more answers

Hamburger buns come in packages of 8. Hamburger patties come in packages of 10.

Vadim26 [7]

Answers/Step-by-step explanation:

A. LCM

B. Greatest Common Factor(GCF) shows the largest whole number, in this case patties and buns, would be a part of the whole that matches both numbers. Neil is unable to buy parts of packages because that not how most stores do business. Least common multiple(LCM) is the number that is both closest in value to the original number while being equal for all numbers. in that case, Neil is buying whole packages so it would work.

C. Neil would buy 4 packages of hamburger patties and 5 packages of hamburger buns. He could make 20 burgers.

3 0

3 years ago

Eight classrooms need to be painted. Teachers can choose between yellow or blue. How many possible outcomes are there?

rusak2 [61]

The answer is 16 outcomes, there are two possible outcomes per classroom, and there are 8 classrooms

7 0

2 years ago

Read 2 more answers

Please help times running out

denpristay [2]

Answer: c