Pleaseeeee helppppp...

Will mark Brianliest please answer :)

Brilliant_brown [7]

Answer:

3.5×10^4=35000

Step-by-step explanation:

Consider the value

3.5

we are saying that we are counting in units (1's) in that we have

3

1

2

of 1's

'.....................................................................................

Consider the value

3.5

×

10

. Now we are saying we have

3

1

2

of tens. That is; 3 lots of 10 is 30 and

1

2

of 10 is 5 so we have

30

+

5

=

35

'.................................................................................

Note that

10

2

is 100

Consider the value

3.5

×

10

2

. Now we are saying we have

3

1

2

of

100

'

s

So if we are counting in 100's then the decimal point stays where

it is and we move the number of 3.5 to the left until the

3 becomes hundreds.

Note that we have to insert a place holder of 0 just to the left of the decimal point to make sure the three is viewed as in the hundreds.

3.5

×

10

2

−−−−−−−−−−−−−−−−−−→

slide to the left 2 places

350.0

6 0

2 years ago

Need help with my homework

Volgvan

Answer:

$\displaystyle y=\frac{16-9x^3}{2x^3 - 3}$

$\displaystyle y=-\frac{56}{13}$

Step-by-step explanation:

<u>Equation Solving</u>

We are given the equation:

$\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}$

i)

To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.

We have to make it in steps like follows.

Cube both sides:

$\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3$

Simplify the radical with the cube:

$\displaystyle x^3=\frac{3y+16}{2y+9}$

Multiply by 2y+9

$\displaystyle x^3(2y+9)=\frac{3y+16}{2y+9}(2y+9)$

Simplify:

$\displaystyle x^3(2y+9)=3y+16$

Operate the parentheses:

$\displaystyle x^3(2y)+x^3(9)=3y+16$

$\displaystyle 2x^3y+9x^3=3y+16$

Subtract 3y and $9x^3$ :

$\displaystyle 2x^3y - 3y=16-9x^3$

Factor y out of the left side:

$\displaystyle y(2x^3 - 3)=16-9x^3$

Divide by $2x^3 - 3$ :

$\mathbf{\displaystyle y=\frac{16-9x^3}{2x^3 - 3}}$

ii) To find y when x=2, substitute:

$\displaystyle y=\frac{16-9\cdot 2^3}{2\cdot 2^3 - 3}$

$\displaystyle y=\frac{16-9\cdot 8}{2\cdot 8 - 3}$

$\displaystyle y=\frac{16-72}{16- 3}$

$\displaystyle y=\frac{-56}{13}$

$\mathbf{\displaystyle y=-\frac{56}{13}}$

8 0

2 years ago

If line q bisects EG at point T, and if ET= 1/3 x and TG= x-2, then find EG

kvasek [131]

Answer:

EG = 2 units

Step-by-step explanation:

Given that line q bisects EG at T , then

ET = TG ( substitute values )

$\frac{1}{3}$ x = x - 2 ( multiply through by 3 to clear the fraction )

x = 3x - 6 ( subtract x from both sides )

0 = 2x - 6 ( add 6 to both sides )

6 = 2x ( divide both sides by 2 )

3 = x

Then

ET = $\frac{1}{3}$ x = $\frac{1}{3}$ × 3 = 1

TG = x - 2 = 3 - 2 = 1

Thus

EG = ET + TG = 1 + 1 = 2 units

8 0

2 years ago

Read 2 more answers

If 3:y=18:24 find y.

VashaNatasha [74]

y = 4

Explanation: $\begin{gathered} 3\text{ : y = 18 : 24} \\ 3\colon y\text{ = }\frac{3}{y} \\ 18\colon24\text{ = }\frac{18}{24} \end{gathered}$ $\begin{gathered} \frac{3}{y}\text{ = }\frac{18}{24} \\ \text{cross mult}iply\colon \\ 3(24)\text{ = y(18)} \\ \text{divide both sides by 18:} \\ \frac{3(24)}{18}\text{ = }\frac{18y}{18} \end{gathered}$ $\begin{gathered} y\text{ = }\frac{24}{6} \\ y\text{ = 4} \end{gathered}$

7 0

1 year ago

Decrease <br>133 in the ratio 7:2

love history [14]

Answer:

38

Step-by-step explanation

2/7× 133=38

6 0

2 years ago