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arlik [135]
3 years ago
8

Pleaseeeee helppppp...

Mathematics
1 answer:
AnnyKZ [126]3 years ago
6 0

Answer:

2 days

Step-by-step explanation:

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there are 60 teams attend a chess tournament. every team will play with every other team exactly once. Supposed each team has a
Karolina [17]

The probability that no two teams win the same number of games, P ≈ 2.084 × 10⁻⁴⁵³

The reason for arriving at the above probability is as follows:

The given parameters are;

The number of teams in the tournament, n = 60

The chance of a team winning a game = 50% = 0.5

The number of ties = No ties

The required parameter:

The probability that no two teams win the same number of games

Method:

Calculate the number of ways no two teams win the same number of games, and divide the result by the total number of possible outcomes

Solution:

The number of matches played, n = \dbinom {60} {2} = 1,770

The possible outcomes = 2; Winning or losing

The total number of possible outcomes, n_p = 2¹⁷⁷⁰

The number of games won by each team is between 0 and 59

The ways in which no two teams won the same number of games is given by the games won by the teams to be 0, 1, 2,..., 57, 58, 59

Therefore, the number of ways no two teams won the same number of games, the required outcomes, n_k = 59!

Probability = \dfrac{Number \ of \ possible \ outcomes}{Number \ of \ required\ outcomes}

The probability that no two teams win the same number of games is given as follows;

\mathbf{P(No \ two \ teams \ won \ the \ same \ number \ of \ games)} = \dfrac{n_k}{n_p}

Therefore;

P(No \ two \ teams \ won \ the \ same \ number \ of \ games) = \dfrac{59!}{2^{1,770}} \approx \mathbf{2.084 \times 10^{-453}}

The probability that no two teams win the same number of games, P ≈ 2.084 × 10⁻⁴⁵³

Learn more about probability theory here:

brainly.com/question/1539712

3 0
2 years ago
The reciprocal of a fraction must be found to solve the problem. What is the reciprocal fraction that is required?
kolezko [41]
6/31 is the answer for your question.
3 0
2 years ago
Read 2 more answers
Triple a number, x, increased by 1 is between -20 and 10. What are the solutions for x?
Bumek [7]
Hello,
-20 \leq 3x+1 \leq 10\\
\Rightarrow\ -21 \leq 3x \leq 9\\
\Rightarrow\ -7 \leq x \leq 3\\

Sol=[-7\ 3]\ if\ x\ is\ a\ real.


3 0
2 years ago
The 6th term of a gp is -2/29,and it's first term is 18.what is the common ratio​
Ymorist [56]

Answer:

-0.329

Step-by-step explanation:

The formula for Geometric ratio is

an = ar^n - 1

Where

a = First term = 18

r = Common ratio = ?

n = Number of term= 6

Hence

a6 = 18 × r^6-1

From the question

a6 = -2/29

Hence:

-2/29 = 18 × r^6-1

-2/29 = 18 × r⁵

Divide both sides by 18

-2/29 ÷ 18 = 18 × r⁵/18

-2/29 × 1/18 = r⁵

r⁵ = -1/261

Take the fifth root of both sides

⁵√(r⁵) = ⁵√(-1/261)

r = -0.3286032834

Approximately = -0.329

Therefore, Common ratio = -0.329

7 0
3 years ago
Solve the inequality for x. Show each step of the solution. 10x>8(3x-2)-12
Anettt [7]

Answer:

x < 2

Step-by-step explanation:

Given

10x > 8(3x - 2) - 12 ← distribute parenthesis on right side

10x > 24x - 16 - 12, that is

10x > 24x - 28 ( subtract 24x from both sides )

- 14x > - 28

Divide both sides by - 14, reversing the inequality symbol as a result of dividing by a negative quantity.

x < 2

8 0
3 years ago
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