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3 years ago

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This year, lashonda watched 85 movies. She thought that 34 of them were very good. If the movies she watched, what percentage di

d she think were very good

1 answer:

Dovator [93]3 years ago

6 0

Answer:

40 percentage

Step-by-step explanation:

sana makatulong I'm not sure

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Bus A and Bus B leave the bus depot at 5 pm. Bus A takes 30 minutes to complete its route once and bus B takes 35 minutes to com

shepuryov [24]

Answer:

Step-by-step explanation:

Bus A will take 1 hour and will arrive back at 6pm, because 30+30=60 and there are 60 min is one hour. Bus B will arrive 1 hour 10 minuets. 35+35=70, Knowing that it will arrive there in over an our because there is more than 60 min, and the extra ten is the amount of minuets. SO bus B will arrive at 6:10pm. Hope I explained this right.

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3 years ago

What is the slope of the line represented by the equation y=-3x+7

xxMikexx [17]

The Slope of this line is -3

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4 years ago

Read 2 more answers

Please answer this question

Vladimir [108]

Answer:

a = 3/2
b = -1/2

Step-by-step explanation:

$\dfrac{\sqrt{5}-1}{\sqrt{5}+1}=\dfrac{(\sqrt{5}-1)(\sqrt{5}-1)}{(\sqrt{5}+1)(\sqrt{5}-1)}\\\\=\dfrac{5-2\sqrt{5}+1}{5-1}=\dfrac{6-2\sqrt{5}}{4}\\\\=\dfrac{3}{2}-\dfrac{1}{2}\sqrt{5}$

Comparing this to the form a+b√5, we see that ...

a = 3/2

b = -1/2

8 0

3 years ago

A cable hangs between two poles of equal height and 35 feet apart. At a point on the ground directly under the cable and x feet

gayaneshka [121]

Answer:

293.38 pounds

Step-by-step explanation:

We are given that

Distance between poles=35 feet

$h(x)=10+0.1(x^{1.5})$

Weight of cable=10.4 per linear foot

We have to find the weight of the cable.

Differentiate w.r.t

$h'(x)=0.1(1.5)x^{0.5}=0.15x^{0.5}$

$s=2\int_{0}^{17.5}\sqrt{1+(h'(x))^2}dx$

$s=2\int_{0}^{17.5}\sqrt{1+(0.15x^{0.5})^2}dx$

$s=2\int_{0}^{17.5}\sqrt{1+0.0225x}dx$

Let $1+0.0225x=t$

$dx=\frac{1}{0.0225}dt$

$s=\frac{2}{0.0225}\int_{0}^{17.5}\sqrt{t}dt$

$s=\frac{2}{0.0225}\times\frac{2}{3}[t^{\frac{3}{2}}]^{17.5}_{0}$

$s=2\times \frac{2}{3\times0.0225}[(1+0.0255x)^{\frac{3}{2}]^{17.5}_{0}$

$s=\frac{4}{3\times 0.0225}((1+0.0225(17.5))^{\frac{3}{2}-1)$

s=28.21

Weight of cable= $28.21\times 10.4=293.38$ pound

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3 years ago

Encuentra el valor de la incógnita -24/x = 6

Marat540 [252]

Answer:

x = -4

The solution is x = -4

3 0

3 years ago