<span>Images are available in many formats, such as tif, bmp, gif, jpeg, and png.
</span>Hope that helps.
Answer:
import java.util.Scanner;
class Main {
public static void main(String args[]) {
Scanner scan = new Scanner(System.in);
System.out.print("Enter a decimal value (0 to 15): ");
int num = scan.nextInt();
scan.close();
if (num < 0 || num >15) {
System.out.printf("%d is an invalid input\n", num);
} else {
System.out.printf("The hex value is %X\n", num);
}
}
}
Explanation:
Hopefully this example will get you going for the other assignments.
by typing ctrl+ s on keyboard
Answer:
Option 1: May crash at runtime because it can input more elements than the array can hold
Explanation:
Given the code as follows:
- int[] a = {1, 3, 7, 0, 0, 0};
- int size = 3, capacity = 6;
- int value = cin.nextInt();
- while (value > 0)
- {
- a[size] = value;
- size++;
- value = cin.nextInt();
- }
From the code above, we know the <em>a</em> is an array with six elements (Line 1). Since the array has been initialized with six elements, the capacity of the array cannot be altered in later stage.
However, a while loop is created to keep prompting for user input an integer and overwrite the value in the array started from index 3 (Line 4- 9). In every round of loop, the index is incremented by 1 (Line 7). If the user input for variable <em>value</em> is always above zero, the while loop will persist. This may reach a point where the index value is out of bound and crash the program. Please note the maximum index value for the array is supposedly be 5.
Is there a picture to go along with this? I don’t see one and an willing to help!
