If the length of a certain rectangle is decreased by 4cm and the width is increased by 3cm,a square with the same area would res
ult.find the perimeter of original rectangle
1 answer:
Answer:
The perimeter is 50
Step-by-step explanation:
The original area is LW
The new area is (L-4)(W+3)
These areas are the same
1: (L-4)(W+3)=LW
You are also told that the new figure is a square, hence
2: (L-4)=(W+3)
Equation (2) implies
3: L=W+7
Substitute for L in Equation (1) and solve for W
(W+7-4)(W+3)=(W+7)W
W^2+3W+7W+21-4W-12=W^2+7W
6W+9=7W
W=9
Now use Equation (3) to solve for L
L=16
The perimeter is 2W+2L
P=18+32=50
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