6/74 i think. So #banananutmuffin/#muffinsintotal
Bc u dont write ur work down. If u actually take the steps to do the question it wont be that bad
Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
Answer: Subtract 6 from both sides. Then, one would get 3x=15. Divde by 3 on both sides. x=5.
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
4/5x+2<7/5x+5
subtract 7/5x from both sides
-3/5x<3
multiply both sides by 5/(-3)
x>-5