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Genrish500 [490]

3 years ago

7

A professional volleyball player can jump an average of 2.5 times higher than the average person. If an average person can jump

inches high, how high can the professional volleyball player jump?

1 answer:

nalin [4]3 years ago

8 0

I = inches.
2.5*i= the answer

All I need to know is the actual number of inches so that i can give you the exact answer

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neonofarm [45]

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3 years ago

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Alinara [238K]

Answer: $y=\frac{1}{4}x-3$

Step-by-step explanation:

- The equation of the line in the slope intercept form is: $y=mx+b$

Where m is the slope and b is the y-intercept of the line

- Let's choose two points of the line: (8,-1) and (-4,-4).

- You must calculate the slope of the line as following:

$m=\frac{y_2-y_1}{x_2-x_1}=\frac{-4-(-1)}{-4-8}=\frac{1}{4}$

- As you can see in the graph attached, the line intersects the y-axis at -3, then b=-3.

- Substituting values into the equation of the line, you obtain:

$y=\frac{1}{4}x-3$

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3 years ago

Let X be the number of Heads in 10 fair coin tosses. (a) Find the conditional PMF of X, given that the first two tosses both lan

inn [45]

Answer:

Follows are the solution to the given point:

Step-by-step explanation:

For option A:

In the first point let z be the number of heads which is available on the first two trails of tosses so, the equation is:

$P(X=k | z=2 ) = \begin{pmatrix} 10-2\\ k-2\end{pmatrix} (\frac{1}{2})^{k-2} (\frac{1}{2})^{10-k}$

$= \begin{pmatrix} 8\\k-2\end{pmatrix} (\frac{1}{2})^{k-2} (\frac{1}{2})^{10-k} \ \ \ \ \ \ \ \ \ \ \\\\$

$k= 2,3..........10$ For option B:

$P(X=k | X \geq 2 ) = \sum^{10}_{i=2} \begin{pmatrix} 10-i\\ k-i\end{pmatrix} (\frac{1}{2})^{k-i} (\frac{1}{2})^{10-k}$

$k= 2,3, 4.........10$

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mariarad [96]

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2 years ago