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3 years ago

Need help quick please

Mathematics

1 answer:

Alecsey [184]3 years ago

7 0

Answer:

agree

Step-by-step explanation:

You might be interested in

Y= 2x + 6 for x = 0,1,2,3,4

algol [13]

x=0 y=6

x=1 y=8

x=2 y=10

x=3 y=12

x=4 y=14

8 0

3 years ago

PLEASE HELP ME SHOW ME HOW U GOT YOUR ANSWER PLZ AND THANK U

lara [203]

Answer:

2/3

Step-by-step explanation:

There are 6 marbles in the jar

4 are not purple

P(not purple) = marbles that are not purple/ total marbles

= 4/6 = 2/3

3 0

3 years ago

Read 2 more answers

if the ratio of similarity of the figures above is 2/3, then what is the ratio of the perimeters of the two figures?

Mademuasel [1]

Perimeter = side 1 + side 2 ´+ side 3.

Triangle 1

Perimeter = 6 + 8 + 10

= 24

Triangle 2

Perimeter = 9 + 12 + 15

= 36

Ratio

24/36 = 2/3

The ratio of the perimeters is also 2/3

5 0

1 year ago

The function f(x)= -6x+11 has a range given by {-37,-25,-13,-1}.Select the domain values of the function from the list 1,2,3,4,5

andreev551 [17]

The range is {-37,-25,-13,-1}. So you need to figure out what four numbers from this list of numbers (1,2,3,4,5,6,7,8), when applied to this
function, ( f(x)=-6x+11 ), equals these numbers that are in the range {-37,-25,-13,-1}.

So you apply each of these numbers (1,2,3,4,5,6,7,8) into the function (f(x)=-6x+11)
one by one.

f(1)=-6(1)+11=5
f(2)=-6(2)+11= -1
f(3)=-6(3)+11= -7
f(4)=-6(4)+11= -13
f(5)=-6(5)+11= -19
f(6)=-6(6)+11= -25
f(7)=-6(7)+11= -31
f(8)=-6(8)+11= -37
As you can see, f(2),f(4),f(6),and f(8) equal the numbers that are in the range {-37,-25,-13,-1}.

4 0

3 years ago

Assume that military aircraft use ejection seats designed for men weighing between 141.8 lb and 218 lb. If women's weights are

Mariulka [41]

Answer:

$P(141.8$

And we can find this probability with this difference and using the normal standard table:

$P(-0.639$

Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women

Step-by-step explanation:

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(173.6,49.8)$

Where $\mu=173.6$ and $\sigma=49.8$

We are interested on this probability

$P(141.8$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(141.8$

And we can find this probability with this difference and using the normal standard table:

$P(-0.639$

Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women

8 0

3 years ago