Put the other line in point slope form...(solve for y :D )
3y=15x+9
y=5x+3, so this line has a slope of 5
For a line to be perpendicular to another the slopes have to be negative reciprocals of each other...mathematically...
s1*s2=-1
So for the other line to be perpendicular to the first:
5m=-1, m=-1/5, thus our other line (so far) is:
y=b-x/5, now we can use the point (-8,-1) to solve for the y-intercept, "b":
-1=b-(-8)/5
-1=b+8/5
-1=b+1.6
b=-2.6
So the perpendicular line that contains the point (-8,-1) is:
y=-0.2x-2.6
Y=-1/2x+5 slope=-1/2 because it goes down one unit and to the right 2 units, and the y intercept is 5 because that's where the line intercepts the y-axis!
Payment on Plan A = $300
x is the number of hours Jake works.
Payment on Plan B = Fixed charges + (charge per hour) × (number of hours worked)
= $150 + $6.25(x)
= 150 + 6.25x
Since, the payment on Plan B should be more than Plan A,
150 + 6.25x > 300
6.25x > 300 - 150
6.25x > 150

x > 24
The minimum vale for x which satisfies this inequality is 25.
Hence, x = 25.
3 to the negative second power is written like this:

.
When simplifying an expression with a negative exponent, you take a positive version of the exponent, in this case that would be 2, and apply that to the base.
After doing that, we have 9.
The next step is to put one over that number.
In this case, now after doing that the answer is

.
Hope this helps!
Adjacent angles<span> are two </span>angles<span> that have a common vertex and a common side.
<OPN and <TSP have a common side but do not have a common vertex.
<OPN and <RSU do not have a common side or a common vertex.
<OPN and <QPN are adjacent angles. They have a common side and a common vertex.
<OPN and <QPS have common vertex but do not have a common side.</span>