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valina [46]
4 years ago
6

Rounded to the nearest 10 as possible

Mathematics
1 answer:
WITCHER [35]4 years ago
7 0

Answer:

What are we rounding?

Step-by-step explanation:

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Step-by-step explanation:

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Type the slope intercept equation of the line that passes through the points (3, -2) and (6, 4)
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3 years ago
Please help! is about Quadratic functions
motikmotik
Vertex:(-1,-4)
Concavity: up
Domain: -♾< x < ♾
Range: y > (or equal to) -4
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6 0
4 years ago
Find factors of x³+12x²-19x= -20
AleksAgata [21]

Answer:

No Factors

Step-by-step explanation:

x^3-12x^2-19x+20 = 0\\Let \ p(x) = x^3-12x^2-19x+20

Factors of 20 = ±1, ±2 , ±4 , ±5 , ±10 and ±20

±1, ±2 and ±3 are not the factors of given polynomial.

Putting x = 4 in the given polynomial

p(4) = (4)^3+12(4)^2-19(4)+20\\p(4) = 64+192-76+20\\p(4) = 200

So, x = 4 is not a factor of p(x)

Putting x = -4 in the given equation

p(-4) = (-4)^3+12(-4)^2-19(4)+20\\p(-4) = -64+192-76+20\\p(-4) = 73

So, x = -4 in the given equation

Putting x = 5 in the given equation

p(5) = (5)^3+12(5)^2-19(5)+20\\p(5) = 125+300-95+20\\p(5) = 350

So, x = 5 is not a factor of p(x)

Putting x = -5 in the given equation

p(-5) = (-5)^3+12(-5)^2-19(-5)+20\\p(-5) = -125+300+95+20\\p(-5) = 290

So, x = -5 is not a factor of p(x)

Putting x = 10 in the given equation

p(10) = (10)^3+12(10)^2-19(10)+20\\p(10) = 1000+1200-190+20\\p(10) = 2030

So, x = 10 is not a factor of p(x)

Putting x = -10 in the given equation

p(-10) = (-10)^3+12(-10)^2-19(-10)+20\\p(-10) = -1000+1200+190+20\\p(-10) = 410

So, x = -10 is not a factor of p(x)

Putting x = 20 in the given equation

p(20) = (20)^3+12(20)^2-19(20)+20\\p(20) = 8000+4800-380+20\\p(20) = 12440

So, x = 20 is not a factor of p(x)

Putting x = -20 in the given equation

p(-20) = (-20)^3+12(-20)^2-19(-20)+20\\p(-20) = -8000+4800+380+20\\p(-20) = -2800

So, x = -20 is not a factor of p(x)

From the above solution, we conclude that the given equation can not be factorized and thus, has no factors.

6 0
3 years ago
Read 2 more answers
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