<u>Answer:</u>
Vt = 4071.5 ft^3
<u>Step-by-step explanation:</u>
Givens:
Equations
- V = (4/3)(pi)r^3
Find: Vt (Total Volume)
Vt = (1/2)V1 + (1/2)(V2)
Vt = (1/2)(V1 + V2) <em>[Factor out (4/3) and (pi) from volumes]</em>
Vt = (1/2)(4/3)(pi)(R^3 + r^3) <em>[Sub in Values]</em>
Vt = 4071.5 ft^3
Answer:
<h2>Hyy There !! </h2>
Step-by-step explanation:
<h3><u>Question Says :- </u></h3>
• The Area of a sector when r = 9/2 and
θ = 5pi/6 radians ? .
? pi / ?
<h3><u>Circular Area of a Sector</u></h3>
Problems involving area of a sector can be solved easily. One should just obtain two essential information from the circle of interest, the central angle measure θ and radius r For angle measures in radians, the area A is calculated as :-
<h3>A = 1/2r^2θ. </h3>
<h3>Hope this helps you !! </h3>
Answer: h= 5/g−3/2
Step-by-step explanation:
h= 5 over g minus 3 over 2
3% x 10 years is 30%. 47 - 30% is 14.1 or 14
Answer:
The standard form of a quadratic equation is:
, 
Quadratic Formula Derivation:
Completing the Square:
Square Root property:
