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3 years ago

A group of friends really love to go bowling together. Here are a set of final scores from a recent bowling trip:

Mathematics

1 answer:

STatiana [176]3 years ago

6 0

Answer:

$Mean = 109.364$

Step-by-step explanation:

Given

$Data: 147, 160, 80, 110, 121, 164, 62, 90, 76, 83, 110$

Required

Calculate the mean

Mean is calculated as:

$Mean = \frac{\sum x}{n}$

In this case:

$n = 11$

So, we have:

$Mean = \frac{147+ 160+ 80+ 110+ 121+ 164+ 62+ 90+ 76+ 83+ 110}{11}$

$Mean = \frac{1203}{11}$

$Mean = 109.364$ -- approximated

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Find X: J:58 K:70 L:111 M:121

Mars2501 [29]

Answer:

Step-by-step explanation:

interior angle formula so

(number of sides - 2)*180

2*180 = 360

you can also just take an example from a square 4*90 = 360

360-121-58-70 = 111

8 0

2 years ago

1 10.) How long was the

spin [16.1K]

Answer:

time =

3.29

Step-by-step explanation:

I= Pnr,

n=?

$n = 299 \div (1300 \times \frac{7}{100} ) \\ \: \: \: \: \: \: \: \: = 3.29(approximatey)$

thanks...

6 0

3 years ago

Dan buys a car for £700. It depreciates at a rate of 5.5% per year. How much will it be worth in 6 years? Give your answer to th

VLD [36.1K]

Answer:

$469

Step-by-step explanation:

To find the amount of money that the car loses in value every year, multiply the price of the car by the rate its value depreciates at in decimal form.

The car depreciates at a rate of 5.5% per year. To find 5.5% in decimal form, move the decimal point to left twice. So, 5.5% in decimal form is 0.055.

700 * 0.055 = 38.5

The car loses $38.50 in value every year, so the car's value will depreciate by 6 times that amount in 6 years.

$38.50 * 6 = $231, so the car will lose $231 in value after 6 years.

700 - 231 = 469

The car will be worth $469 in 6 years.

3 0

3 years ago

Jan's All You Can Eat Restaurant charges $9.10 per customer to eat at the restaurant. Restaurant management finds that its exp

Nikolay [14]

Answer:

Step-by-step explanation:

From the given question;

Given that:

Jan's All You Can Eat Restaurant charges $9.10 per customer to eat at the restaurant.

Distribution is skewed and and has a mean of $8.10 and a standard deviation of $4.

A. If the 100 customers on a day have the characteristics of the random sample from their customer base, find the mean and standard error of the sampling distribution of the restaurant's sample mean expense per customer.

the mean by using the central limit theorem is 8.10

the standard error of the sampling distribution = $\dfrac{\sigma}{\sqrt{n}}$