Answer:
and
.
Step-by-step explanation:
So I believe the problem is this:

where we are asked to find values for
and
such that the equation holds for any
in the equation's domain.
So I'm actually going to get rid of any domain restrictions by multiplying both sides by (x-3)(x+7).
In other words this will clear the fractions.


As you can see there was some cancellation.
I'm going to plug in -7 for x because x+7 becomes 0 then.




Divide both sides by -10:


Now we have:
with 
I notice that x-3 is 0 when x=3. So I'm going to replace x with 3.




Divide both sides by 10:


So
and
.
Answer:
lol it is 7 90 3
Step-by-step explanation:
They would need to by 3 more tickets. 214 divided by 9 = 23 with the remainder of 3. So I divided 217 by 9 = 23. I added 3 to 214 which got a whole answer 23.
I hope I helped.