Prostatic acid phosphatase was purified from prostatic fluid. Monospecific antisera to the purified acid phosphatase was then produced in rabbits. When antibody was coupled with acid phosphatase, the enzymatic activity was markedly stabilized against pH and temperature degradation. Both acid phosphatase and rabbit anti acid phosphatase were non specifically coupled to Sepharose-4B using cyanogen bromide. Under these circumstances slight stability occurred when antibody was bound to Sepharose, and then acid phosphatase added to the gel antibody complex. When acid phosphatase was complexed to Sepharose, no stabilization occurred.
Answers
Some provide nutrients for each other
Explanation:
No because a chemical reaction that is at equilibrium in living cells is not capable of doing any work
Answer:
Man's genotype: Bbdd
Woman's genotype: bbDd
First child's genotype: Bbdd
Second child's genotype: bbDd
Explanation:
This is a dihybrid cross involving two genes; one coding for eye color and the other for hair color in humans. The allele for brown eye (B) is dominant over the allele for blue eyes (b) in the first gene while the allele for dark hair (D) is dominant over the allele for red hair (d) in the second gene.
According to the question, A man with brown eyes and red hair will possibly possess genotypes: BBdd or Bbdd while a woman with blue eyes and dark hair will possibly have genotype: bbDD or bbDd. Considering the fact that they produced children with recessive traits for both gene (blue eyes and red hair), it means that they are heterozygous for their dominant trait. This means that the ideal genotype for the man is Bbdd since he will produce gametes containing B and b alleles for the first gene while the ideal genotype for the woman is bbDd since it will produce gametes with D and d allele for the second gene.
Hence, a child with brown eyes and red hair will possess genotype: Bbdd since he/she cannot receive two dominant alleles for the first gene from both parents. A child with blue eyes and dark hair will have genotype: bbDd since he/she cannot receive two dominant alleles of the second gene from both parents.
