Question

Answer. it fast please​

Answer 1

Answer:

$(\frac{3}{4})^3 * (\frac{2}{3})^2 = \frac{3}{16}$

Step-by-step explanation:

Given

$(\frac{3}{4})^3 * (\frac{2}{3})^2$

Required

Solve:

$(\frac{3}{4})^3 * (\frac{2}{3})^2$

Apply law of indices

$(\frac{3}{4})^3 * (\frac{2}{3})^2 = \frac{3^3}{4^3} * \frac{2^2}{3^2}$

Express 4 as 2^2

$(\frac{3}{4})^3 * (\frac{2}{3})^2 = \frac{3^3}{(2^2)^3} * \frac{2^2}{3^2}$

$(\frac{3}{4})^3 * (\frac{2}{3})^2 = \frac{3^3}{2^6} * \frac{2^2}{3^2}$

Express as a singe fraction

$(\frac{3}{4})^3 * (\frac{2}{3})^2 = \frac{3^3*2^2}{2^6*3^2}$

Apply law of indices:

$(\frac{3}{4})^3 * (\frac{2}{3})^2 = \frac{3^{3-2}}{2^{6-2}}$

$(\frac{3}{4})^3 * (\frac{2}{3})^2 = \frac{3^1}{2^4}$

$(\frac{3}{4})^3 * (\frac{2}{3})^2 = \frac{3}{16}$