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andreyandreev [35.5K]
3 years ago
5

How do I solve -24x+6y=18;-8+2y=6 by using the system of elimination?

Mathematics
1 answer:
jeyben [28]3 years ago
7 0

\left\{\begin{array}{ccc}-24x+6y=18\\-8x+2y=6&\text{multiply both sides by (-3)}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}-24x+6y=18\\24x-6y=-18\end{array}\right}\qquad\text{add both sides of equations}\\.\qquad\qquad0=0\\\\Answer:\ \boxed{\text{The system is dependent }}\\\\\left\{\begin{array}{ccc}x\in\mathbb{R}\\y=4x+3\end{array}\right

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Zoe's Fish tank holds 27 L of water she uses a 3L container to fill the tank how many times does she have to fill the three litt
Marianna [84]
<h2>Answer:</h2>

Zoe's Fish tank holds 27 L of water, so this is the capacity of the tank. On the other hand, Zoe uses a 3L container in order to fill the tank, so the question is  how many times does she have to fill the three litter container in order to fill the fish tank? Let's solve this as follows:

First time:

She pours 3L

Second time:

She pours another 3L, but she previously poured 3L, so she has poured 6L

Third time:

She pours another 3L, but she previously poured 6L, so she has poured 9L

Fourth time:

She pours another 3L, but she previously poured 9L, so she has poured 12L

Fifth time:

She pours another 3L, but she previously poured 12L, so she has poured 15L

Sixth time:

She pours another 3L, but she previously poured 15L, so she has poured 18L

Seventh time:

She pours another 3L, but she previously poured 18L, so she has poured 21L

Eighth time:

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Ninth time:

She pours another 3L, but she previously poured 24L, so she has poured 27L

<em>According to this, she needs to pours the </em><em>3L </em><em>container nine times in order to fill the fish tank. This can also be solved dividing </em><em>27L/3L= 9</em>

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