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joja [24]
3 years ago
7

A 6th grade math teacher can grade 15 homework assignments in 24 minutes. If he works at the same rate, how long should it take

him to grade 36 homework assignments?[type your answer as a decimal number]
Mathematics
1 answer:
coldgirl [10]3 years ago
4 0

Answer:

57.6

Step-by-step explanation:

If hê works 15 grades in 24 min how long hê will take to finish 36 grades

15 grades= 24 min

36 grades=?

Cress cross

15grades?=24min x 36grades

15 grades?=864 min grades

15grades/15grades?=864mingrades/15grades

?=57.6 min

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Because of her work schedule, Molly Kay plans to take classes at 8:00, 10:00, and 11:00. Five courses that fit her program are o
pychu [463]

Answer: There are 90 different schedules are possible for Molly Kay.

Step-by-step explanation:

Since we have given that

Three time scheduled at 8:00, 10:00, 11:00.

Number of courses offer at 8:00 = 5

Number of courses offer at 10:00 = 9

Number of courses offer at 11:00 = 2

So, the number of different schedules are possible for Molly Kay is given by

^{5}C_1\times ^9C_1\times ^2C_1\\\\=5\times 9\times 2\\\\=45\times 2\\\\=90

Hence, there are 90 different schedules are possible for Molly Kay.

7 0
3 years ago
U<br> th<br> th<br> V<br> 3<br> D<br> F<br> Geometry
loris [4]

Answer:

interesting can i get brainliest

Step-by-step explanation:

8 0
3 years ago
Evaluate the following integrals: 1. Z x 4 ln x dx 2. Z arcsin y dy 3. Z e −θ cos(3θ) dθ 4. Z 1 0 x 3 √ 4 + x 2 dx 5. Z π/8 0 co
Zigmanuir [339]

Answer:

The integrals was calculated.

Step-by-step explanation:

We calculate integrals, and we get:

1) ∫ x^4 ln(x) dx=\frac{x^5 · ln(x)}{5} - \frac{x^5}{25}

2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}

3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}

4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}

5)  \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=

=\frac{3π+8}{64}

6)  ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x

7) ∫ sec^4 (x) tan^3 (x) dx = \frac{tan^6(x)}{6} + \frac{tan^4(x)}{4}

8)  ∫ tan^5 (x) sec(x)  dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x

6 0
4 years ago
Yoo wtm!!!!!!!!!!!!!!!!!!!!!!!!!!!!
olga2289 [7]

Answer: what's ur question

Step-by-step explanation:

8 0
4 years ago
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On a map 3 inches represent and actual distance of 42 miles if the actual distance between two cities is 322 miles how many inch
Artyom0805 [142]

Answer:

if 3 inches on a map = 42miles

then x = 322miles

cross multiply

3inches by 322 = xby42miles

966inchesmiles = 42xinchesmiles

divide both sides by 42miles

xinchees = 23

therefore 322miles distance will take 23inches on a map

4 0
3 years ago
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