Question

Line p passes through points (6, 8) and (2, 11). Line q is perpendicular to p. What is the slope of line q?

Answer 1

Answer:

Step-by-step explanation:

Slope of p=$\frac{11-8}{2-6}$

                 = -$\frac{3}{4}$

∵line q is perpendicular to p

∴Slope of q x slop of p=-1

Slope of line q=$\frac{4}{3}$