6. Solve the problem.
1 answer:
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Answer:
<h2><em>46.4°</em></h2>Step-by-step explanation:
Find the diagrammatic representation in the attachment given.
We can see that the diagram is a right angled triangle. To get the angle of elevation, we will use one of the trigonometry identity SOH, CAH, TOA.
Given the adjacent of the triangle to be 2miles (observation spot from the point of launch)and the opposite (side facing the elevation angle) as 2.1miles (the height), we will use TOA.
tan∅ = opposite/adjacent
tan∅ = 2.1/2
tan∅ = 1.05
∅ = tan⁻¹1.05
∅ = 46.4°
<em>Hence the angle of elevation from Kim to the space shuttle, which is at a height of 2.1 miles is approximately 46.4°</em>
Answer:
Length of the shadow of the pole is 6.93 metres
Step-by-step explanation:
Given:
Height of the pole = 4 m
The angle sun makes with the horizontal = 30 degrees
To Find:
Length of the shadow of the pole = ?
Solution:
The tangent ratio is the value received when the length of the side opposite of angle theta is divided by the length of the side adjacent to angle theta
Let x be the length of the shadow
According to the tangent ratio
On substituting the values,
x = 6.93 m
