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Anarel [89]
3 years ago
5

Plz help me I’ll make brainliest

Mathematics
2 answers:
arlik [135]3 years ago
6 0

Answer:

m=4 because 2 times 4 is 8 and n= 8 because 2 times 8 is 16

Step-by-step explanation:

love history [14]3 years ago
5 0

Answer:

7

Step-by-step explanation:

You might be interested in
What’s 8 squared into a decimal
ycow [4]

Answer:

2.828 i think

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
The moon has a diameter of approximately 2,200 miles. If the circumference of a circle can be found using the formula C = πd, wh
Anna007 [38]

Answer:6908 (miles) ^2

Step-by-step explanation:

diameter=2200 miles

π=3.14

Circumference=π x diameter

Circumference=3.14 x 2200

Circumference=6908 (miles)^2

4 0
3 years ago
70 points and i’ll give brainliest!! please answer all the questions on the page! must show work and how you got the answer. ple
Bezzdna [24]

6. One variable only so pretty straightforward.

length-x+4

width-x

x+x+4=80

2x=76

x=38

x+4=42

answer: length 42cm and width 38cm

7. Another money problem!

n-# of nickels

q-# of quarters

n=3+q

0.05n+0.25q=2.85

Substitution works like a charm!

0.05(3+q)+0.25q=2.85

0.15+0.05q+0.25q=2.85

0.3q=2.7

q=9

n=3+q

n=3+9

n=12

answer: 9 nickels and 12 quarters

8. One variable situation again.

Ann's money-2b+9

Betty's money-b

b+2b+9=60

3b=51

b=17

2b+9=43

answer: Ann has $43 and Betty has $17.

9. # of red m&m's-x+1

# of blue m&m's-x

x+1+x=13

x=6

x+1=7

answer: 6 blue and 7 red m&m's

10. a-number of adult tickets

s-number of student tickets

a+s=785 ----> a=785-s

5a+2s=3280

5(785-s)+2s=3280

-3s=-645

s=215

a+s=785

a+215=785

a=570

answer: 215 children tickets and 570 adult tickets

3 0
3 years ago
What is the image of (0,-8)(0,−8) after a reflection over the line y=-xy=−x?
AnnZ [28]

Answer:

(8, 0 )

Step-by-step explanation:

under a reflection in the line y = - x

a point (x, y ) → (- y, - x ) , then

(0, - 8 ) → (8, 0 )

5 0
1 year ago
A student S is suspected of cheating on exam, due to evidence E of cheating being present. Suppose that in the case of a cheatin
Kay [80]

Answer:

Step-by-step explanation:

Suppose we think of an alphabet X to be the Event of the evidence.

Also, if Y be the Event of cheating; &

Y' be the Event of not involved in cheating

From the given information:

P(\dfrac{X}{Y}) = 60\% = 0.6

P(\dfrac{X}{Y'}) = 0.01\% = 0.0001

P(Y) = 0.01

Thus, P(Y') \ will\ be = 1 - P(Y)

P(Y') = 1 - 0.01

P(Y') = 0.99

The probability of cheating & the evidence is present is = P(YX)

P(YX) = P(\dfrac{X}{Y}) \ P(Y)

P(YX) =0.6 \times 0.01

P(YX) =0.006

The probabilities of not involved in cheating & the evidence are present is:

P(Y'X) = P(Y')  \times P(\dfrac{X}{Y'})

P(Y'X) = 0.99  \times 0.0001 \\ \\  P(Y'X) = 0.000099

(b)

The required probability that the evidence is present is:

P(YX  or Y'X) = 0.006 + 0.000099

P(YX  or Y'X) = 0.006099

(c)

The required probability that (S) cheat provided the evidence being present is:

Using Bayes Theorem

P(\dfrac{Y}{X}) = \dfrac{P(YX)}{P(Y)}

P(\dfrac{Y}{X}) = \dfrac{P(0.006)}{P(0.006099)}

P(\dfrac{Y}{X}) = 0.9838

5 0
3 years ago
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