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3 years ago

Find the measure of each angle

Mathematics

1 answer:

pychu [463]3 years ago

4 0

Answer:

Answer is in the screenshot provided.

Step-by-step explanation:

Work is also in the screenshot provided.

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Mother spent 1/3 of her money on a silver chain and 1/6 of the remainder on a bottle of perfume. She gave her daughter $60.00 an

Volgvan

Step-by-step explanation:

215÷3=71

143÷6=23.9

71+23.9+60=154.9

7 0

3 years ago

Enter your answers in the boxes to correctly complete this statement.

harina [27]

Answer:

349800

Step-by-step explanation:

First Part:

The question tells you to multiply by 10 to the power of 4.

This implies that you can move the decimal point 4 numbers to the right

When you move the decimal two numbers to the right you get 3498

Then you got to move it two more numbers to the right

3498 can also be written as 3498.0000000000 (infinite amount of zeros)

So moving the decimal two more places you get 349800

Second Part:

10^4 = 10 * 10 * 10 * 10

= 10000

Count the zeros you get 4.

3 0

3 years ago

In october 2012, apple introduced a much smaller variant of the apple ipad, known as the ipad mini. weighing less than 11 ounces

Allushta [10]

F(x) = $\left \{ {{1} \atop {3.5}} \right.$ 8.5≤
0

8 0

3 years ago

Read 2 more answers

Is the equation y=3x in slope intercept form

makkiz [27]

No y=mx+b your missing the b in the formula which stands for y intercept

3 0

3 years ago

A sample survey is designed to estimate the proportion of sports utility vehicles being driven in the state of California. A ran

mart [117]

Answer:

a) The 95% confidence interval would be given (0.070;0.121).

b) "increase the sample size n"

"decrease za/2 by decreasing the confidence"

Step-by-step explanation:

Notation and definitions

$X=48$ number of vehicles classified as sports utility.

$n=500$ random sample taken

$\hat p=\frac{48}{500}=0.096$ estimated proportion of vehicles classified as sports utility vehicles.

$p$ true population proportion of vehicles classified as sports utility vehicles.

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

(a) Use a 95% confidence interval to estimate the proportion of sports utility vehicles in California. (Round your answers to three decimal places.)

The confidence interval would be given by this formula :

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.5=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$0.096 - 1.96 \sqrt{\frac{0.096(1-0.096)}{500}}=0.070$

$0.096 + 1.96 \sqrt{\frac{0.096(1-0.096)}{500}}=0.121$

And the 95% confidence interval would be given (0.070;0.121).

We are confident (95%) that about 7.0% to 12.1% of vehicles in California are classified as sports utility .

(b) How can you estimate the proportion of sports utility vehicles in California with a higher degree of accuracy? (HINT: There are two answers. Select all that apply.)

For this case we just have two ways to increase the accuracy one is "increase the sample size n" since if we have a larger sample size the estimation would be more accurate. And the other possibility is "decrease za/2 by decreasing the confidence" because if we decrease the confidence level the interval would be narrower and accurate

7 0

3 years ago