This is essentially asking how many different ways to partition 6 into 3 segments.
I am assuming "no ball in a box" is not allowed.
6 can be partitioned as
(4,1,1), (3,2,1), and (2,2,2)
So, calculate each partition, we get
(6 choose 4) + (6 choose 3)*(3 choose 2) + (6 choose 2) * (4 choose 2)
= 15 + 20*3 + 15*6
=165
Answer:
theres not alot of info it just says boys, and ends there
Step-by-step explanation:
1,3,5 because they are all negatives less than -3
Answer:
182
Step-by-step explanation:
The correct answer is 182 because to figure out the total we needed to multiply the 2 sides, a quicker way instead of counting. To do this you needed to multiply 13 times 14 and you would get 182!
Hope this helped!
Please mark as best answer if right!
